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Input string was not in a correct format

I'm new with C#, I have some basic knowledge in Java but I can't get this code to run properly.

It's just a basic calculator, but when I run the program VS2008 gives me this error:

Calculator

I did almost the same program but in java using JSwing and it worked perfectly.

Here's the form of c#:

Form

using System;
using System.Collections.Generic;
using System.ComponentModel;
using System.Data;
using System.Drawing;
using System.Linq;
using System.Text;
using System.Windows.Forms;

namespace calculadorac
{
    public partial class Form1 : Form
    {

    int a, b, c;
    String resultado;

    public Form1()
    {
        InitializeComponent();
        a = Int32.Parse(textBox1.Text);
        b = Int32.Parse(textBox2.Text);
    }

    private void button1_Click(object sender, EventArgs e)
    {
        add();
        result();
    }

    private void button2_Click(object sender, EventArgs e)
    {
        substract();
        result();
    }

    private void button3_Click(object sender, EventArgs e)
    {
        clear();
    }

    private void add()
    {
        c = a + b;
        resultado = Convert.ToString(c);
    }

    private void substract()
    {
        c = a - b;
        resultado = Convert.ToString(c);
    }

    private void result()
    {
        label1.Text = resultado;
    }

    private void clear()
    {
        label1.Text = "";
        textBox1.Text = "";
        textBox2.Text = "";
    }
}

What can be the problem? Is there a way to solve it?

PS: I also tried

a = Convert.ToInt32(textBox1.text);
b = Convert.ToInt32(textBox2.text);

and it didn't work.

like image 759
kustomrtr Avatar asked Nov 30 '11 05:11

kustomrtr


People also ask

How do I fix the input string was not in a correct format?

Input string was not in a correct format error occurs when you convert non-numeric data into an int or exceed the limit of the int data type. You should use Int. TryParse instead of Int32. Parse method to get rid of the said error.

What is an input string?

String input templates allow you to specify the type, order, and number of characters a user can enter in a data entry field. You can define string input templates only on single‑line character data entry fields.

How do I format a string in C#?

Example 1: C# String Format() string strFormat = String. Format("There are {0} apples.", number); Here, "There are {0} apples." is a format string.


7 Answers

The error means that the string you're trying to parse an integer from doesn't actually contain a valid integer.

It's extremely unlikely that the text boxes will contain a valid integer immediately when the form is created - which is where you're getting the integer values. It would make much more sense to update a and b in the button click events (in the same way that you are in the constructor). Also, check out the Int.TryParse method - it's much easier to use if the string might not actually contain an integer - it doesn't throw an exception so it's easier to recover from.

like image 132
Jon Avatar answered Oct 05 '22 08:10

Jon


I ran into this exact exception, except it had nothing to do with parsing numerical inputs. So this isn't an answer to the OP's question, but I think it's acceptable to share the knowledge.

I'd declared a string and was formatting it for use with JQTree which requires curly braces ({}). You have to use doubled curly braces for it to be accepted as a properly formatted string:

string measurements = string.empty;
measurements += string.Format(@"
    {{label: 'Measurement Name: {0}',
        children: [
            {{label: 'Measured Value: {1}'}},
            {{label: 'Min: {2}'}},
            {{label: 'Max: {3}'}},
            {{label: 'Measured String: {4}'}},
            {{label: 'Expected String: {5}'}},
        ]
    }},",
    drv["MeasurementName"] == null ? "NULL" : drv["MeasurementName"],
    drv["MeasuredValue"] == null ? "NULL" : drv["MeasuredValue"],
    drv["Min"] == null ? "NULL" : drv["Min"],
    drv["Max"] == null ? "NULL" : drv["Max"],
    drv["MeasuredString"] == null ? "NULL" : drv["MeasuredString"],
    drv["ExpectedString"] == null ? "NULL" : drv["ExpectedString"]);

Hopefully this will help other folks who find this question but aren't parsing numerical data.

like image 36
delliottg Avatar answered Oct 05 '22 06:10

delliottg


If you are not validating explicitly for numbers in the text field, in any case its better to use

int result=0;
if(int.TryParse(textBox1.Text,out result))

Now if the result is success then you can proceed with your calculations.

like image 25
V4Vendetta Avatar answered Oct 05 '22 08:10

V4Vendetta


Problems

There are some possible cases why the error occurs:

  1. Because textBox1.Text contains only number, but the number is too big/too small

  2. Because textBox1.Text contains:

    • a) non-number (except space in the beginning/end, - in the beginning) and/or
    • b) thousand separators in the applied culture for your code without specifying NumberStyles.AllowThousands or you specify NumberStyles.AllowThousands but put wrong thousand separator in the culture and/or
    • c) decimal separator (which should not exist in int parsing)

NOT OK Examples:

Case 1

a = Int32.Parse("5000000000"); //5 billions, too large
b = Int32.Parse("-5000000000"); //-5 billions, too small
//The limit for int (32-bit integer) is only from -2,147,483,648 to 2,147,483,647

Case 2 a)

a = Int32.Parse("a189"); //having a 
a = Int32.Parse("1-89"); //having - but not in the beginning
a = Int32.Parse("18 9"); //having space, but not in the beginning or end

Case 2 b)

NumberStyles styles = NumberStyles.AllowThousands;
a = Int32.Parse("1,189"); //not OK, no NumberStyles.AllowThousands
b = Int32.Parse("1,189", styles, new CultureInfo("fr-FR")); //not OK, having NumberStyles.AllowThousands but the culture specified use different thousand separator

Case 2 c)

NumberStyles styles = NumberStyles.AllowDecimalPoint;
a = Int32.Parse("1.189", styles); //wrong, int parse cannot parse decimal point at all!

Seemingly NOT OK, but actually OK Examples:

Case 2 a) OK

a = Int32.Parse("-189"); //having - but in the beginning
b = Int32.Parse(" 189 "); //having space, but in the beginning or end

Case 2 b) OK

NumberStyles styles = NumberStyles.AllowThousands;
a = Int32.Parse("1,189", styles); //ok, having NumberStyles.AllowThousands in the correct culture
b = Int32.Parse("1 189", styles, new CultureInfo("fr-FR")); //ok, having NumberStyles.AllowThousands and correct thousand separator is used for "fr-FR" culture

Solutions

In all cases, please check the value of textBox1.Text with your Visual Studio debugger and make sure that it has purely-acceptable numerical format for int range. Something like this:

1234

Also, you may consider of

  1. using TryParse instead of Parse to ensure that the non-parsed number does not cause you exception problem.
  2. check the result of TryParse and handle it if not true

    int val;
    bool result = int.TryParse(textbox1.Text, out val);
    if (!result)
        return; //something has gone wrong
    //OK, continue using val
    
like image 25
Ian Avatar answered Oct 05 '22 06:10

Ian


In my case I forgot to put double curly brace to escape. {{myobject}}

like image 33
zawhtut Avatar answered Oct 05 '22 06:10

zawhtut


You may encounter this exception when you use a string formatter with invalid bracket syntax.

// incorrect
string.Format("str {incorrect}", "replacement")

// correct
string.Format("str {1}", "replacement")
like image 31
quemeful Avatar answered Oct 05 '22 06:10

quemeful


You have not mentioned if your textbox have values in design time or now. When form initializes text box may not hae value if you have not put it in textbox when during form design. you can put int value in form design by setting text property in desgin and this should work.

like image 29
Kirtan Pandya Avatar answered Oct 05 '22 08:10

Kirtan Pandya