Initializing a Char*[]

Question

Question is in the title, how do I initialize a char*[] and give values to it in C++, thank you.

Answer 1

Though you're probably aware, char*[] is an array of pointers to characters, and I would guess you want to store a number of strings. Initializing an array of such pointers is as simple as:

char ** array = new char *[SIZE]; 

...or if you're allocating memory on the stack:

char * array[SIZE]; 

You would then probably want to fill the array with a loop such as:

for(unsigned int i = 0; i < SIZE; i++){     // str is likely to be an array of characters     array[i] = str; } 

As noted in the comments for this answer, if you're allocating the array with new (dynamic allocation) remember to delete your array with:

delete[] array; 

Answer 2

Depending on what you want to initialize to you could do any of:

char mystr[] = {'h','i',0}; char * myotherstring = "my other string"; char * mythirdstring = "goodbye";  char * myarr[] = {0}; char * myarr[] = {&mystr, myotherstring}; char * myarr[10]; char * myarr[10] = {0}; char * myarr[10] = {&mystr, myotherstring, mythirdstring, 0}; 

etc. etc.