C++ methods allow a const
qualifier to indicate that the object is not changed by the method. But what does that mean? Eg. if the instance variables are pointers, does it mean that the pointers are not changed, or also that the memory to which they point is not changed?
Concretely, here is a minimal example class
class myclass { int * data; myclass() { data = new int[10]; } ~myclass() { delete [] data; } void set(const int index) const { data[index] = 1; } };
Does the method set
correctly qualify as const
? It does not change the member variable data
, but it sure does change the content of the array.
Const Functions The effects of declaring a variable to be const propagate throughout the program. Once you have a const object, it cannot be assigned to a non-const reference or use functions that are known to be capable of changing the state of the object.
A function becomes const when the const keyword is used in the function's declaration. The idea of const functions is not to allow them to modify the object on which they are called. It is recommended the practice to make as many functions const as possible so that accidental changes to objects are avoided.
The const means that the method promises not to alter any members of the class. You'd be able to execute the object's members that are so marked, even if the object itself were marked const : const foobar fb; fb.
Because the data type being pointed to is const, the value being pointed to can't be changed. We can also make a pointer itself constant. A const pointer is a pointer whose address can not be changed after initialization.
What can a 'const' method change?
Without explicitly casting away constness, a const
method can change:
mutable
data members, andconst
access to, irrespective of whether that data's accessible: For members of class
/struct
/union
type, it relies on the constness of their member functions to determine which operations should be allowed. (It can also change any non-const local variables and by-value parameters, but I know that's not what you're interested in).
It can call other const
methods which will have these same abilities and restrictions.
Eg. if the instance variables are pointers, does it mean that the pointers are not changed, or also that the memory to which they point is not changed?
It means the pointers can't be (easily/accidentally) changed. It does not mean that the pointed-to memory can't be changed.
What you've stumbled on is the logical incorrectness of a const
function changing pointed-to or referenced data conceptually owned by the object. As you've found, the compiler doesn't enforce the const
correctness you may want or expect here. That's a bit dangerous, but means constness doesn't need to be explicitly removed for pointers/references to other objects which may be changed as a side-effect of the const
function. For example, a logging object. (Typically, such objects are not logically "owned" by the object whose const
function is operating on them.) The key point is that the compiler can't reliably distinguish the type of logical ownership an object has over pointed-to data, so it's got to guess one way or the other and allow the programmer to either override, or not be protected by const
-ness. C++ forgoes the protection.
Interesting, I've heard Walter Bright's D language flips this default, making pointed-to data const
by default in const
functions. That's seems safer to me, though it's hard to imagine how often one would end up needing to explicitly cast away constness to allow wanted side-effects, and whether that would feel satisfyingly precise or annoyingly verbose.
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