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Is there a more efficient, simpler way to create a tuple of lists of length 'n'?
So in Python, if I wanted to create a list of lists I could do something like:
[[] for _ in range(list_length)]
And to create a tuple of lists of a similar nature I could technically write:
tuple([[] for _ in range(list_length)])
But is this computationally inefficient, could it be written in a nicer way?
Warning: For anyone else who thought it was good idea to put mutable objects such as lists inside a tuple (immutable); it actually appears to be generally faster (computationally) to just use a list (in my case a list of lists).
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Initialize a TupleYou can initialize an empty tuple by having () with no values in them. You can also initialize an empty tuple by using the tuple function. A tuple with values can be initialized by making a sequence of values separated by commas.
Python tuple method len() returns the number of elements in the tuple.
How to assign a tuple of length 1 to a? A parenthesized expression list yields whatever that expression list yields: if the list contains at least one comma, it yields a tuple; otherwise, it yields the single expression that makes up the expression list.
Use a genex instead of a LC.
tuple([] for _ in range(list_length))
Try this:
tuple = (elements,) * list_length
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