Index of multiple minimum elements in a list [duplicate]

Question

I want a list

a = [2,4,5,2]

to give

b = [0, 3]

I know how to do it for when there is only a single min element, but not multiple min elements. example:

b = a.index(min(a))

This will give me b = 0.

Answer 1

Find the minimum value, then iterate the list with index using enumerate to find the minimum values:

>>> a = [2,4,5,2]
>>> min_value = min(a)
>>> [i for i, x in enumerate(a) if x == min_value]
[0, 3]