I have a list of strings
x = ['A', 'B', nan, 'D']
and want to remove the nan.
I tried:
x = x[~numpy.isnan(x)]
But that only works if it contains numbers. How do we solve this for strings in Python 3+?
If you have a numpy array you can simply check the item is not the string nan
, but if you have a list you can check the identity with is
and np.nan
since it's a singleton object.
In [25]: x = np.array(['A', 'B', np.nan, 'D'])
In [26]: x
Out[26]:
array(['A', 'B', 'nan', 'D'],
dtype='<U3')
In [27]: x[x != 'nan']
Out[27]:
array(['A', 'B', 'D'],
dtype='<U3')
In [28]: x = ['A', 'B', np.nan, 'D']
In [30]: [i for i in x if i is not np.nan]
Out[30]: ['A', 'B', 'D']
Or as a functional approach in case you have a python list:
In [34]: from operator import is_not
In [35]: from functools import partial
In [37]: f = partial(is_not, np.nan)
In [38]: x = ['A', 'B', np.nan, 'D']
In [39]: list(filter(f, x))
Out[39]: ['A', 'B', 'D']
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