I have created a project with SQL Server which the files:
UserDAO.java*
public class UserDAO
{
private static SessionFactory sessionFactory;
static
{
sessionFactory = HibernateUtility.getSessionFactory();
}
@SuppressWarnings("unchecked")
public static List<User> findAll()
{
Session session = sessionFactory.openSession();
Criteria crit = session.createCriteria(User.class);
List<User> userList = crit.list();
return userList;
}
}
UserService.java
public class UserService
{
public static void main(String[] args)
{
List<User> listUsers = UserDAO.findAll();
for(User u : listUsers)
{
System.out.println("User is = " + u.getUserName());
}
}
}
hibernate.cfg.xml
<?xml version="1.0" encoding="utf-8"?>
<!DOCTYPE hibernate-configuration PUBLIC
"-//Hibernate/Hibernate Configuration DTD//EN"
"http://www.hibernate.org/dtd/hibernate-configuration-3.0.dtd">
<hibernate-configuration>
<session-factory>
<property name="hibernate.dialect">org.hibernate.dialect.SQLServer2008Dialect</property>
<property name="hibernate.connection.driver_class">com.microsoft.sqlserver.jdbc.SQLServerDriver</property>
<property name="hibernate.connection.url">jdbc:sqlserver://localhost:1433;database=happy</property>
<property name="hibernate.connection.username">lm</property>
<property name="hibernate.connection.password">pp</property>
<property name="hibernate.hbm2ddl.auto">create</property>
<property name="show_sql">true</property>
<property name="hibernate.current_session_context_class">thread</property>
<property name="hibernate.hbm2ddl.auto">validate</property>
<mapping class="com.annotation.day1.entity.User"/>
</session-factory>
</hibernate-configuration>
After running the project, the exception bellow displayed:
Hibernate:
select
this_.id as id1_0_0_,
this_.password as password2_0_0_,
this_.userName as userName3_0_0_
from
User this_
Aug 07, 2016 9:29:00 PM org.hibernate.engine.jdbc.spi.SqlExceptionHelper logExceptions
WARN: SQL Error: 156, SQLState: S0001
Aug 07, 2016 9:29:00 PM org.hibernate.engine.jdbc.spi.SqlExceptionHelper logExceptions
ERROR: Incorrect syntax near the keyword 'User'.
Exception in thread "main" org.hibernate.exception.SQLGrammarException: could not extract ResultSet
at org.hibernate.exception.internal.SQLStateConversionDelegate.convert(SQLStateConversionDelegate.java:123)
at org.hibernate.exception.internal.StandardSQLExceptionConverter.convert(StandardSQLExceptionConverter.java:49)
at org.hibernate.engine.jdbc.spi.SqlExceptionHelper.convert(SqlExceptionHelper.java:126)
at org.hibernate.engine.jdbc.spi.SqlExceptionHelper.convert(SqlExceptionHelper.java:112)
at org.hibernate.engine.jdbc.internal.ResultSetReturnImpl.extract(ResultSetReturnImpl.java:89)
at org.hibernate.loader.Loader.getResultSet(Loader.java:2065)
at org.hibernate.loader.Loader.executeQueryStatement(Loader.java:1862)
at org.hibernate.loader.Loader.executeQueryStatement(Loader.java:1838)
at org.hibernate.loader.Loader.doQuery(Loader.java:909)
at org.hibernate.loader.Loader.doQueryAndInitializeNonLazyCollections(Loader.java:354)
at org.hibernate.loader.Loader.doList(Loader.java:2553)
at org.hibernate.loader.Loader.doList(Loader.java:2539)
at org.hibernate.loader.Loader.listIgnoreQueryCache(Loader.java:2369)
at org.hibernate.loader.Loader.list(Loader.java:2364)
at org.hibernate.loader.criteria.CriteriaLoader.list(CriteriaLoader.java:126)
at org.hibernate.internal.SessionImpl.list(SessionImpl.java:1682)
at org.hibernate.internal.CriteriaImpl.list(CriteriaImpl.java:380)
at com.annotation.day1.dao.UserDAO.findAll(UserDAO.java:74)
at com.annotation.day1.service.UserService.main(UserService.java:24)
Caused by: com.microsoft.sqlserver.jdbc.SQLServerException: Incorrect syntax near the keyword 'User'.
at com.microsoft.sqlserver.jdbc.SQLServerException.makeFromDatabaseError(SQLServerException.java:197)
Any help is appreciated. Thanks in advance.
USER
is a Reserve Word and needs to be escaped in query using square bracket []
while querying.
If you are using annotations, escape through single quotes. ''
, like below
@Table(name="`user`")
Also refer here for similar issue.
Faced pretty similar issue, when Column name value has space in between.
Note : Hibernate 5.3.7 with SQLServer 2014
@Entity
@Table(name = "TableName")
public class Customer {
@Id
@Column(name = "cid")
@GeneratedValue(strategy = GenerationType.IDENTITY)
private int customerId;
@Column(name = "Customer Name")
private String customerName;
---
---
ERROR:
Solution 1 : Template Literals
Solution 2:
-We could remove the space or add '_' in between
@Column(name = "CustomerName") or @Column(name = "Customer_Name")
Note: Name is also a reserved word in SQLServer.
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