Im trying to make class A a friend of class B.
class B;
class A{
public:
void show(const B&); // ##1## but this one works fine
B ob;// error incomplete type
};
class B{
public:
int b;
B():b(1){}
friend class A;
};
so my question why it's incomplete type? I thought that when I did class B
it's like a prototype of a function which tell the compile there is a definition somewhere in the code.
also in the code above at ##1## why this is possible ?
No, that's a forward declaration and does not define a full type. You'll need to have a full definition of B
before A
, if you want to keep the member as an object and not pointer.
One of the reason for this is that the size of the class B
must be known to A
, since A
's size depends on B
.
I suggest you #include "B.h"
in A.h
.
EDIT: clarification:
struct A;
struct B
{
A foo();
void foo(A);
void foo(A&);
void foo(A*);
A* _a;
A& __a;
A a; // <--- only error here
};
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