In MongoDB's pymongo, how do I do a count()?

Question

for post in db.datasets.find({"test_set":"abc"}).sort("abc",pymongo.DESCENDING).skip((page-1)*num).limit(num): 

This is my current code.

How do I get the count() ?

Answer 1

If you're using pymongo version 3.7.0 or higher, see this answer instead.

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If you want results_count to ignore your limit():

results = db.datasets.find({"test_set":"abc"}).sort("abc",pymongo.DESCENDING).skip((page-1)*num).limit(num) results_count = results.count()  for post in results: 

If you want the results_count to be capped at your limit(), set applySkipLimit to True:

results = db.datasets.find({"test_set":"abc"}).sort("abc",pymongo.DESCENDING).skip((page-1)*num).limit(num) results_count = results.count(True)  for post in results: 

Answer 2

Since pymongo version 3.7.0 and above count() is deprecated. Instead use Collection.count_documents. Running cursor.count or collection.count will result in following warning message:

DeprecationWarning: count is deprecated. Use Collection.count_documents instead. 

To use count_documents the code can be adjusted as follows

import pymongo  db = pymongo.MongoClient() col = db[DATABASE][COLLECTION]  find = {"test_set":"abc"} sort = [("abc",pymongo.DESCENDING)] skip = 10 limit = 10  doc_count = col.count_documents(find, skip=skip) results = col.find(find).sort(sort).skip(skip).limit(limit)  for doc in result:    //Process Document 

Note: count_documents method performs relatively slow as compared to count method. In order to optimize you can use collection.estimated_document_count. This method will return estimated number of docs(as the name suggested) based on collection metadata.