In Linux shell script how do i print the largest and smallest values of a array?

Question

I dont really understand much about arrays but i need to know how to find and print the largest and smallest values of an array. The array is predefined by a read command, the user will be prompted to enter n amount of integers.

How would i assign the read input to an array and find and display the largest and smallest values of the array?

Is there a way to test the array elements to see if they are all integers?

#!/bin/bash

read -a integers

biggest=${integers[0]}
smallest=${integers[0]}

for i in ${integers[@]}
do
     if [[ $i -gt $biggest ]]
     then
        biggest="$i"
     fi

     if [[ $i -lt $smallest ]]
     then
        smallest="$i"
     fi
done

echo "The largest number is $biggest"
echo "The smallest number is $smallest"

Answer 1

The general idea is to iterate through the array once and keep track of what the max and min seen so far at each step.

Some comments and explanations in-line (prefixed by #)

# This is how to declare / initialize an array:
arrayName=(1 2 3 4 5 6 7)

# Use choose first element of array as initial values for min/max;
# (Defensive programming) - this is a language-agnostic 'gotcha' when
# finding min/max ;)
max=${arrayName[0]}
min=${arrayName[0]}

# Loop through all elements in the array
for i in "${arrayName[@]}"
do
    # Update max if applicable
    if [[ "$i" -gt "$max" ]]; then
        max="$i"
    fi

    # Update min if applicable
    if [[ "$i" -lt "$min" ]]; then
        min="$i"
    fi
done

# Output results:
echo "Max is: $max"
echo "Min is: $min"