In Java super.getClass() prints "Child" not "Parent" - why is that?

Question

In Java classes and objects, we use "this" keyword to reference to the current object within the class. In some sense, I believe "this" actually returns the object of itself.

Example for this:

class Lion
{
    public void Test()
    {
        System.out.println(this);  //prints itself (A Lion object)
    }
}

---

In the scenario of a superclass and subclass. I thought that "super" keyword would return the object of the superclass. However it seems that I got it wrong this time:

Example:

class Parent
{
    public Parent(){
    }
}

class Child extends Parent
{
    public Child(){
        System.out.println(super.getClass()); //returns Child. Why?
    }
}

My Quesiton: In the above example, I was expecting the compiler to print out class Parent, however it prints out class Child. Why is this so? What super actually returns?

Answer 1

A method call using super just ignores any overrides in the current class. For example:

class Parent {
    @Override public String toString() {
        return "Parent";
    }
}

class Child extends Parent {
    @Override public String toString() {
        return "Child";
    }

    public void callToString() {
        System.out.println(toString()); // "Child"
        System.out.println(super.toString()); // "Parent"
    }
}

In the case of a call to getClass(), that's a method which returns the class it's called on, and can't be overridden - so while I can see why you'd possibly expect it to return Parent.class, it's still using the same implementation as normal, returning Child. (If you actually want the parent class, you should look at the Class API.)

This is often used as part of an override, in fact. For example:

@Override public void validate() {
    // Allow the parent class to validate first...
    super.validate();
    // ... then perform child-specific validation
    if (someChildField == 0) {
        throw new SomeValidationException("...");
    }
}