In Java 8, transform Optional<String> of an empty String in Optional.empty

Question

Given a String I need to get an Optional, whereby if the String is null or empty the result would be Optional.empty. I can do it this way:

String ppo = ""; Optional<String> ostr = Optional.ofNullable(ppo); if (ostr.isPresent() && ostr.get().isEmpty()) {     ostr = Optional.empty(); } 

But surely there must be a more elegant way.

Answer 1

You could use a filter:

Optional<String> ostr = Optional.ofNullable(ppo).filter(s -> !s.isEmpty()); 

That will return an empty Optional if ppo is null or empty.

Answer 2

With Apache Commons:

.filter(StringUtils::isNotEmpty)