in bash script, see and use the exact entire command line

Question

Is there any way to access the exact command line as typed?

(After variable expansion is OK)

It's the only way I can think of to achieve the following:

myscript.sh file1 file2 file3 -m"A multi word comment" [other parameters/options]

-- and inside the script we effectively call --

svn commit file1 file2 file3 -m"A multi word comment" [other parameters/options]

-- without having to duplicate all the parsing that svn does itself, just to make sense of the command line

(The problem I have is that in the example, $4 is going to be "-mA multi word comment" which is going to be a mess to sort out. I'd rather be able to shoot the whole command-line, quotes and all, straight to svn just exactly how svn will want to see it.)

If anyone knows a better way to write an svn "wrapper", I'd also like to hear it.

Answer 1

Have you tried in your script:

svn commit "$@"

Explanation:

• $@ is a special variable that containing all the arguments to the shell, starting at $1.

Answer 2

Inside effectively call you can:

svn commit "$@"

As for seeing exactly how it is typed — no. You can't tell a b from a b (note one and two spaces between parameters — argh, I think even SO hides the second space ;)). But you don't need to.