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Is there a way to test whether an array contains a specified element?
e.g., something like:
array=(one two three)
if [ "one" in ${array} ]; then
...
fi
867
$1 means an input argument and -z means non-defined or empty. You're testing whether an input argument to the script was defined when running the script.
[[ … ]] double brackets are an alternate form of conditional expressions in ksh/bash/zsh with a few additional features, for example you can write [[ -L $file && -f $file ]] to test if a file is a symbolic link to a regular file whereas single brackets require [ -L "$file" ] && [ -f "$file" ] .
bash [filename] runs the commands saved in a file. $@ refers to all of a shell script's command-line arguments. $1 , $2 , etc., refer to the first command-line argument, the second command-line argument, etc.
Bash provides one-dimensional indexed and associative array variables. Any variable may be used as an indexed array; the declare builtin will explicitly declare an array. There is no maximum limit on the size of an array, nor any requirement that members be indexed or assigned contiguously.
A for loop will do the trick.
array=(one two three)
for i in "${array[@]}"; do
if [[ "$i" = "one" ]]; then
...
break
fi
done
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