When I compile and run the code below with either counter++
or ++counter
substituted for x
, the output is identical; in both cases, numbers 1 - 10:
for (int counter = 1; counter < 11; x)
{
std::cout << counter << endl;
}
Originally I thought ++counter
would increment by 1 and then return the new value before for boolean expression in the loop header was evaluated. i.e when starting with counter = 1
and using ++counter
, counter
would have a value of 2 in the boolean expression. This appears to not be the case, as both outputs are identical rather than the ++counter
version having one less iteration, like I expected.
Reading around, it appears ++counter
and counter++
increment counter
by 1 at either the start or end of the loop body respectively. In which case is this not, at least conceptually, an identical action? Because the end and the start of the loop are the same thing once the loop has past the first iteration.
The only time I can see this making a difference is in the first iteration, where std::cout << counter << endl;
should output 1 to the console if counter++
is used (because 1 is added to counter at the end of the loop). Whilst std::cout << counter << endl;
should output 2 to the console if ++counter
is used (because 1 is added to counter at the start of the loop).
In addition to the question above, could you please precisely explain the order in which the three actions are evaluated in the for loop header, and explain exactly where the iterations occur when using i++
and ++i
.
Many thanks!
There is no difference. In older compilers, ++counter
was faster because it did not create a temporary variable but all modern compilers can optimize that out. For heavy objects with custom (non-inlined) increment operators, ++counter
can still be more efficient.
As for when evaluation takes place:
for (initialization; condition; increment/decrement)
code;
is evaluated as
{
initialization;
while (condition)
{
code;
increment/decrement;
}
}
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