I have a problem with opening .csv files with Excel by VBA code. I have data organised like:
Number;Name;Price1;Price2;City
1234;"John Smith";"1,75 EUR";"2,15 EUR";"New Mexico"
3456;"Andy Jahnson";"12,45 EUR";"15,20 EUR";London
3456;"James Bond";"42,34 EUR";"9,20 EUR";Berlin
When I open this file manually by Excel from Windows Explorator, everything looks fine, all values are separated correctly. It looks like that:
When I try to open this by VBA, using
Workbooks.Open fileName:=strPath & "thisFile.csv"
data is separated by commas, so it looks like that:
The same wrong result pops out when I am using OpenText function
Workbooks.OpenText filename:=strPath & "thisFile.csv", DataType:=xlDelimited, _
TextQualifier:=xlDoubleQuote, ConsecutiveDelimiter:=False, Tab:=False, _
Semicolon:=True, Comma:=False, Space:=False, Other:=False
and when I try use solution from this thread. Any ideas?
I hope you are using something newer than Excel 2000. This is what I experience with Excel 2016 on a machine with German format settings: Apparently the Workbooks.Open
options for delimiters (Format
and Delimiter
) are only applied when you open a .txt
file. If Local
is set to False
(the default value), the file will be opened with the VBA language settings, using a comma as delimiter. Setting Local:=True
will prevent this so
Workbooks.Open FileName:=strPath & "thisFile.csv", Local:=True
should work for you. If you rename your file to .txt
, you can use the Format
and Delimiter
options:
Workbooks.Open FileName:=strPath & "thisFile.txt", Format:=4 'Format = 4 is semicolon delimited
Workbooks.Open FileName:=strPath & "thisFile.txt", Format:=6, Delimiter:=";" 'Format = 6 is custom delimited
See MSDN for more details
However this will mess up your decimal numbers, see my edit.
Edit: I misread the documentation. The Format
and Delimiter
options are actually only applied when using a .txt
file and not .csv
(even the .OpenText
method behaves that way).
If you want to make sure it opens on a machine with different format settings the only solution I have right now is to rename it to .txt
and use
Workbooks.OpenText FileName:=strPath & "thisFile.txt", DataType:=xlDelimited, Semicolon:=True, DecimalSeparator:=",", ThousandsSeparator:="."
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