I'm looking to split my gulpfile.js assets or src variables into separate files so that I can manage them better. For example:
....
var scripts = ['awful.js', 'lot.js', 'of.js', 'js.js', 'files.js']
....(somewhere down the line)
gulp.task('vendorjs', function() {
    return gulp.src(scripts)
        .pipe(concat('vendor.js'))
        .pipe(rename({suffix: '.min'}))
        .pipe(uglify())
        .pipe(gulp.dest(paths.root + 'dist'))
        .pipe(notify({ message: 'vendorjs task completed' }));
});
So what I'm basically interested if theres a way to actually move to a separate file the scripts variable and be able to access it from gulpfile.js.
I've been looking into something like:
require("fs").readFile('gulp/test.js', function(e, data) {
   //(test.js would be the file that holds the scripts var)
});
Howerver while it does read the contents of the file, I still can't access it from the gulpfile.js. Any tips or ideas are much appreciated.
Node.js allows you to import other files using require(). It supports three types of files:
For JavaScript files the value returned from require() is the one that is assigned to  module.exports in the imported file. 
So for your use case:
gulp/test.js
var arrayOfFiles = ["awful.js", "lots.js"];
arrayOfFiles.push("of.js");
arrayOfFiles.push("js.js");
arrayOfFiles.push("files.js");
for (var i = 0; i < 10; i++) {
  arrayOfFiles.push("some_other_file" + i + ".js");       
}
module.exports = {
  scripts: arrayOfFiles
};
gulpfile.js
var test = require('gulp/test.js');
gulp.task('vendorjs', function() {
  return gulp.src(test.scripts)
    .pipe(concat('vendor.js'))
    .pipe(rename({suffix: '.min'}))
    .pipe(uglify())
    .pipe(gulp.dest(paths.root + 'dist'))
    .pipe(notify({ message: 'vendorjs task completed' }));
});
                        You could use a json file to store your assets or source file location in and load that into your gulp file.
For example:
// config.json
{
  "scripts": ["awful.js", "lot.js", "of.js", "js.js", "files.js"]
}
And in your gulp file you would do
// gulpfile.js
var config = require('./config');
var scripts = config.scripts;
console.log(scripts);
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