Ignoring separating character using scanf

Question

The problem: I am attempting to use scanf to read a sentence with fields seperate by | ,so naturally i use the scanf's natural features to ignore this symbol but it then also ignores everything that has a | in it.

The code, simplified:

int main(){
    char* a=malloc(8);
    char* b=malloc(8);
    scanf("%s | %s",a,b);
    printf("%s %s",a,b);
}

when i attempt the input:

TEST | ME

it works as intended, but when i have the following case:

TEST ME|

it naturally reads the test, but ignores the ME|, is there any way around this?

Answer 1

    scanf("%[^ \t|]%*[ \t|]%[^ \t\n|]", a,b);
    printf("%s %s",a,b);

Annotation:

%* : ignore this element.

E.g. %*s //skip the reading of the text of this one

%[character set(allow)] : Read only character set that you specify.

E.g. %[0123456789] or %[0-9] //Read as a string only numeric characters

%[^character set(denied)] : It is to mean character other than when ^ is specified at the beginning of the character set.

Answer 2

Yes, you can scan for a character set. The problem you're seeing is not related to the vertical bar, it's the fact that a string stops at the first whitespace character, i.e. the space between "TEST" and "ME|".

So, do something like:

if(scanf("%7[^|] | %7[^|]", a, b) == 2)
{
  a[7] = b[7] = '\0';
  printf("got '%s' and '%s'\n", a, b);
}

See the manual page for scanf() for details on the [ conversion specifier.