Ignoring class members that throw exceptions when serializing to JSON

Question

I'm using the Newtonsoft JSON serializer and it works for most objects.

Unfortunately I get a JsonSerializationException when I try to serialize a large object, one of whose members throws a NullReferenceException.

Is there anyway to ignore the offending member and serialize the rest of the object?

I'm thinking perhaps in the JsonSerializerSettings?

Here's a simplified version of what I want to do:

private class TestExceptionThrowingClass {     public string Name { get { return "The Name"; } }     public string Address { get { throw new NullReferenceException(); } }     public int Age { get { return 30; } } }  [Test] public void CanSerializeAClassWithAnExceptionThrowingMember() {      // Arrange     var toSerialize = new TestExceptionThrowingClass();      // Act      var serializerSettings = new Newtonsoft.Json.JsonSerializerSettings();     serializerSettings.MaxDepth = 5;     serializerSettings.ReferenceLoopHandling = Newtonsoft.Json.ReferenceLoopHandling.Ignore;     serializerSettings.MissingMemberHandling = Newtonsoft.Json.MissingMemberHandling.Ignore;     serializerSettings.NullValueHandling = Newtonsoft.Json.NullValueHandling.Ignore;     serializerSettings.ObjectCreationHandling = Newtonsoft.Json.ObjectCreationHandling.Reuse;     serializerSettings.DefaultValueHandling = Newtonsoft.Json.DefaultValueHandling.Ignore;      var result = Newtonsoft.Json.JsonConvert.SerializeObject(toSerialize);      // Assert     Assert.That(result, Is.EqualTo(@"{""Name"":""The Name"",""Age"":30}")); } 

And here's the stack trace:

at Newtonsoft.Json.Serialization.DynamicValueProvider.GetValue(Object target)  at Newtonsoft.Json.Serialization.JsonSerializerInternalWriter.CalculatePropertyValues(JsonWriter writer, Object value, JsonContainerContract contract, JsonProperty member, JsonProperty property, JsonContract& memberContract, Object& memberValue)  at Newtonsoft.Json.Serialization.JsonSerializerInternalWriter.SerializeObject(JsonWriter writer, Object value, JsonObjectContract contract, JsonProperty member, JsonContainerContract collectionContract, JsonProperty containerProperty)  at Newtonsoft.Json.Serialization.JsonSerializerInternalWriter.SerializeValue(JsonWriter writer, Object value, JsonContract valueContract, JsonProperty member, JsonContainerContract containerContract, JsonProperty containerProperty)  at Newtonsoft.Json.Serialization.JsonSerializerInternalWriter.Serialize(JsonWriter jsonWriter, Object value, Type objectType)  at Newtonsoft.Json.JsonSerializer.SerializeInternal(JsonWriter jsonWriter, Object value, Type objectType)  at Newtonsoft.Json.JsonConvert.SerializeObject(Object value, Type type, Formatting formatting, JsonSerializerSettings settings)  at Newtonsoft.Json.JsonConvert.SerializeObject(Object value)  at AspectsProject.Aspects.CachingPolicy.CachingPolicyCacheKeyCreatorTests.CanSerializeAClassWithAnExceptionThrowingMember() in D:\Dev\test.cs:line 169     --NullReferenceException  at AspectsProject.Aspects.CachingPolicy.CachingPolicyCacheKeyCreatorTests.TestExceptionThrowingClass.get_Address() in D:\Dev\test.cs:line 149  at GetAddress(Object )  at Newtonsoft.Json.Serialization.DynamicValueProvider.GetValue(Object target) 

I'm happy to use a different JSON serializer if someone knows one that will do this.

Answer 1

A simpler way to ignore errors:

JsonSerializerSettings settings = new JsonSerializerSettings(); settings.Error = (serializer,err) => {     err.ErrorContext.Handled = true; } 

or

settings.Error = (serializer,err) => err.ErrorContext.Handled = true;