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ifstream::open not working in Visual Studio debug mode

I've been all over the ifstream questions here on SO and I'm still having trouble reading a simple text file. I'm working with Visual Studio 2008.

Here's my code:

// CPPFileIO.cpp : Defines the entry point for the console application.
//

#include "stdafx.h"
#include <fstream>
#include <conio.h>
#include <iostream>
#include <string>

using namespace std;


int _tmain(int argc, _TCHAR* argv[])
{

    ifstream infile;
    infile.open("input.txt", ifstream::in);

    if (infile.is_open())
    {
        while (infile.good())
            cout << (char) infile.get();
    }
    else
    {
        cout << "Unable to open file.";
    }
    infile.close();
    _getch();
    return 0;
}

I have confirmed that the input.txt file is in the correct "working directory" by checking the value of argv[0]. The Open method just won't work.

I'm also having trouble debugging- should I not be able to set a watch on infile.good() or infile.is_open()? I keep getting

Error: member function not present.

EDIT: Updated code listing with full code from .CPP file.

UPDATE: The file was NOT in the Current Working Directory. This is the directory where the project file is located. Moved it there and it works when debugging in VS.NET.

like image 500
Dave Swersky Avatar asked Apr 28 '09 16:04

Dave Swersky


1 Answers

Try using the bitwise OR operator when specifying the open mode.

infile.open ("input.txt", ios::ate | ios::in);

The openmode parameter is a bitmask. ios::ate is used to open the file for appending, and ios::in is used to open the file for reading input.

If you just want to read the file, you can probably just use:

infile.open ("input.txt", ios::in);

The default open mode for an ifstream is ios::in, so you can get rid of that altogether now. The following code is working for me using g++.

#include <iostream>
#include <fstream>
#include <cstdio>

using namespace std;

int main(int argc, char** argv) {
    ifstream infile;
    infile.open ("input.txt");

    if (infile)
    {
        while (infile.good())
            cout << (char) infile.get();
    }
    else
    {
        cout << "Unable to open file.";
    }
    infile.close();
    getchar();
    return 0;
}
like image 156
Bill the Lizard Avatar answered Nov 10 '22 00:11

Bill the Lizard