If statements without brackets

Question

I'm hoping to get some clarification on if and if else statements that do not have brackets and how to read them. I can read if else, and else if statements with brackets easily and they make sense to me but these have always confused me, here is a sample question.

if (x > 10)      
     if (x > 20)
          printf("YAY\n");    
else      printf("TEST\n");

Answer 1

If there are no brackets on an if/else, the first statement after the if will get executed.

If statement:

if (condition)
    printf("this line will get executed if condition is true");
printf("this line will always get executed");

If/else:

if (condition)
    printf("this line will get executed if condition is true");
else
    printf("this line will get executed if condition is false");
printf("this line will always get executed");

Note: Your code will break if there are multiple commands between an if and its matching else.

if (condition)
    printf("this line will get executed if condition is true");
    printf("this line will always get executed");
else
    printf("this else will break since there is no longer a matching if statement");