Does an if-statement
with an && operator
check for the second parameter if the first one is false
/ NO
?
Would the following be able to crash?
NSDictionary *someRemoteData = [rawJson valueForKey:@"data"];
if( [someRemoteData isKindOfClass:[NSDictionary class]] && someRemoteData.count > 0 ){
//..do something
}
Please no simple yes or no answer, but explain why.
if (score >= 90) grade = 'A'; The following example displays Number is positive if the value of number is greater than or equal to 0 . If the value of number is less than 0 , it displays Number is negative .
The logical AND operator ( && ) returns true if both operands are true and returns false otherwise. The operands are implicitly converted to type bool before evaluation, and the result is of type bool . Logical AND has left-to-right associativity.
An if statement is written with the if keyword, followed by a condition in parentheses, with the code to be executed in between curly brackets. In short, it can be written as if () {} .
No, it does not evaluate the expression after learning that the answer is going to be NO
. This is called short-circuiting, and it is an essential part of evaluating boolean expressions in C, C++, Objective C, and other languages with similar syntax. The conditions are evaluated left to right, making the evaluation scheme predictable.
The same rule applies to the ||
operator: as soon as the code knows that the value is YES
, the evaluation stops.
Short-circuiting lets you guard against invalid evaluation in a single composite expression, rather than opting for an if
statement. For example,
if (index >= 0 && index < Length && array[index] == 42)
would have resulted in undefined behavior if it were not for short-circuiting. But since the evaluation skips evaluation of array[index]
when index
is invalid, the above expression is legal.
Objective-C uses lazy evaluation, which means that only the left operand is evaluated in your case.
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