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If I come from an imperative programming background, how do I wrap my head around the idea of no dynamic variables to keep track of things in Haskell?

So I'm trying to teach myself Haskell. I am currently on the 11th chapter of Learn You a Haskell for Great Good and am doing the 99 Haskell Problems as well as the Project Euler Problems.

Things are going alright, but I find myself constantly doing something whenever I need to keep track of "variables". I just create another function that accepts those "variables" as parameters and recursively feed it different values depending on the situation. To illustrate with an example, here's my solution to Problem 7 of Project Euler, Find the 10001st prime:

answer :: Integer
answer = nthPrime 10001

nthPrime :: Integer -> Integer
nthPrime n
  | n < 1 = -1
  | otherwise = nthPrime' n 1 2 []


nthPrime' :: Integer -> Integer -> Integer -> [Integer] -> Integer
nthPrime' n currentIndex possiblePrime previousPrimes
  | isFactorOfAnyInThisList possiblePrime previousPrimes = nthPrime' n currentIndex theNextPossiblePrime previousPrimes
  | otherwise = 
    if currentIndex == n 
      then possiblePrime 
      else nthPrime' n currentIndexPlusOne theNextPossiblePrime previousPrimesPlusCurrentPrime
        where currentIndexPlusOne = currentIndex + 1
              theNextPossiblePrime = nextPossiblePrime possiblePrime
              previousPrimesPlusCurrentPrime = possiblePrime : previousPrimes

I think you get the idea. Let's also just ignore the fact that this solution can be made to be more efficient, I'm aware of this.

So my question is kind of a two-part question. First, am I going about Haskell all wrong? Am I stuck in the imperative programming mindset and not embracing Haskell as I should? And if so, as I feel I am, how do avoid this? Is there a book or source you can point me to that might help me think more Haskell-like?

Your help is much appreciated,

-Asaf

like image 663
Asaf Avatar asked Dec 09 '11 00:12

Asaf


4 Answers

Am I stuck in the imperative programming mindset and not embracing Haskell as I should?

You are not stuck, at least I don't hope so. What you experience is absolutely normal. While you were working with imperative languages you learned (maybe without knowing) to see programming problems from a very specific perspective - namely in terms of the van Neumann machine.

If you have the problem of, say, making a list that contains some sequence of numbers (lets say we want the first 1000 even numbers), you immediately think of: a linked list implementation (perhaps from the standard library of your programming language), a loop and a variable that you'd set to a starting value and then you would loop for a while, updating the variable by adding 2 and putting it to the end of the list.

See how you mostly think to serve the machine? Memory locations, loops, etc.! In imperative programming, one thinks about how to manipulate certain memory cells in a certain order to arrive at the solution all the time. (This is, btw, one reason why beginners find learning (imperative) programming hard. Non programmers are simply not used to solve problems by reducing it to a sequence of memory operations. Why should they? But once you've learned that, you have the power - in the imperative world. For functional programming you need to unlearn that.)

In functional programming, and especially in Haskell, you merely state the construction law of the list. Because a list is a recursive data structure, this law is of course also recursive. In our case, we could, for example say the following:

constructStartingWith n = n : constructStartingWith (n+2)

And almost done! To arrive at our final list we only have to say where to start and how many we want:

result = take 1000 (constructStartingWith 0)

Note that a more general version of constructStartingWith is available in the library, it is called iterate and it takes not only the starting value but also the function that makes the next list element from the current one:

iterate f n = n : iterate f (f n)
constructStartingWith = iterate (2+)   -- defined in terms of iterate

Another approach is to assume that we had another list our list could be made from easily. For example, if we had the list of the first n integers we could make it easily into the list of even integers by multiplying each element with 2. Now, the list of the first 1000 (non-negative) integers in Haskell is simply

[0..999]

And there is a function map that transforms lists by applying a given function to each argument. The function we want is to double the elements:

double n = 2*n

Hence:

result = map double [0..999]

Later you'll learn more shortcuts. For example, we don't need to define double, but can use a section: (2*) or we could write our list directly as a sequence [0,2..1998]

But not knowing these tricks yet should not make you feel bad! The main challenge you are facing now is to develop a mentality where you see that the problem of constructing the list of the first 1000 even numbers is a two staged one: a) define how the list of all even numbers looks like and b) take a certain portion of that list. Once you start thinking that way you're done even if you still use hand written versions of iterate and take.

Back to the Euler problem: Here we can use the top down method (and a few basic list manipulation functions one should indeed know about: head, drop, filter, any). First, if we had the list of primes already, we can just drop the first 1000 and take the head of the rest to get the 1001th one:

result = head (drop 1000 primes)

We know that after dropping any number of elements form an infinite list, there will still remain a nonempty list to pick the head from, hence, the use of head is justified here. When you're unsure if there are more than 1000 primes, you should write something like:

result = case drop 1000 primes of
    [] -> error "The ancient greeks were wrong! There are less than 1001 primes!"
    (r:_) -> r

Now for the hard part. Not knowing how to proceed, we could write some pseudo code:

primes = 2 : {-an infinite list of numbers that are prime-}

We know for sure that 2 is the first prime, the base case, so to speak, thus we can write it down. The unfilled part gives us something to think about. For example, the list should start at some value that is greater 2 for obvious reason. Hence, refined:

primes = 2 : {- something like [3..] but only the ones that are prime -}

Now, this is the point where there emerges a pattern that one needs to learn to recognize. This is surely a list filtered by a predicate, namely prime-ness (it does not matter that we don't know yet how to check prime-ness, the logical structure is the important point. (And, we can be sure that a test for prime-ness is possible!)). This allows us to write more code:

primes = 2 : filter isPrime [3..]

See? We are almost done. In 3 steps, we have reduced a fairly complex problem in such a way that all that is left to write is a quite simple predicate. Again, we can write in pseudocode:

isPrime n = {- false if any number in 2..n-1 divides n, otherwise true -}

and can refine that. Since this is almost haskell already, it is too easy:

isPrime n = not (any (divides n) [2..n-1])
divides n p = n `rem` p == 0

Note that we did not do optimization yet. For example we can construct the list to be filtered right away to contain only odd numbers, since we know that even ones are not prime. More important, we want to reduce the number of candidates we have to try in isPrime. And here, some mathematical knowledge is needed (the same would be true if you programmed this in C++ or Java, of course), that tells us that it suffices to check if the n we are testing is divisible by any prime number, and that we do not need to check divisibility by prime numbers whose square is greater than n. Fortunately, we have already defined the list of prime numbers and can pick the set of candidates from there! I leave this as exercise.

You'll learn later how to use the standard library and the syntactic sugar like sections, list comprehensions, etc. and you will gradually give up to write your own basic functions.

Even later, when you have to do something in an imperative programming language again, you'll find it very hard to live without infinte lists, higher order functions, immutable data etc. This will be as hard as going back from C to Assembler.

Have fun!

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Ingo Avatar answered Oct 14 '22 08:10

Ingo


It's ok to have an imperative mindset at first. With time you will get more used to things and start seeing the places where you can have more functional programs. Practice makes perfect.

As for working with mutable variables you can kind of keep them for now if you follow the rule of thumb of converting variables into function parameters and iteration into tail recursion.

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hugomg Avatar answered Oct 14 '22 07:10

hugomg


I think the big change from your code to more haskell like code is using higher order functions, pattern matching and laziness better. For example, you could write the nthPrime function like this (using a similar algorithm to what you did, again ignoring efficiency):

nthPrime n = primes !! (n - 1) where
  primes = filter isPrime [2..]
  isPrime p = isPrime' p [2..p - 1]
  isPrime' p [] = True
  isPrime' p (x:xs) 
    | (p `mod` x == 0) = False
    | otherwise = isPrime' p xs

Eg nthPrime 4 returns 7. A few things to note:

  • The isPrime' function uses pattern matching to implement the function, rather than relying on if statements.
  • the primes value is an infinite list of all primes. Since haskell is lazy, this is perfectly acceptable.
  • filter is used rather than reimplemented that behaviour using recursion.

With more experience you will find you will write more idiomatic haskell code - it sortof happens automatically with experience. So don't worry about it, just keep practicing, and reading other people's code.

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David Miani Avatar answered Oct 14 '22 07:10

David Miani


Off the top of my head:

  • Typeclassopedia. The official v1 of the document is a pdf, but the author has moved his v2 efforts to the Haskell wiki.

  • What is a monad? This SO Q&A is the best reference I can find.

  • What is a Monad Transformer? Monad Transformers Step by Step.

  • Learn from masters: Good Haskell source to read and learn from.

  • More advanced topics such as GADTs. There's a video, which does a great job explaining it.

  • And last but not least, #haskell IRC channel. Nothing can even come close to talk to real people.

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edwardw Avatar answered Oct 14 '22 09:10

edwardw