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html and Svg to Canvas javascript

<div id="Contents">
<div style="float:left;margin-left:10px;">
<svg></svg>
</div>
<div style="float:left;margin-left:10px;">
<svg></svg>
</div>
</div>

This is my html code. I want to convert it canvas image.

html2canvas($("#Contents"), {
  onrendered: function(canvas) {
   window.open(canvas.toDataURL());

  }
});

I use html2canvas plugin for convert it to image but It does not show svg. I solve converting svg tp canvas but now html2canvas not working

  var $to=$("#MainContents").clone();

            $($to).children(".box").each(function() {
    var svg = ResizeArray[$(this).children(".box-content").children().attr("new-id")-1].svg();
            var Thiscanvas = document.createElement("canvas");
            Thiscanvas.setAttribute("style", "height:" + 100 + "px;width:" + 100+ "px;");

            canvg(Thiscanvas, svg);

            $(this).append(Thiscanvas);

        });
        html2canvas($($to), {
      onrendered: function(canvasq) {
        var w=window.open(canvasq.toDataURL());
        w.print();
      }
    });

I can convert svg to canvas but html2canvas function not working.

like image 292
user2622044 Avatar asked Aug 16 '13 11:08

user2622044


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3 Answers

You will need to use canvg library for drawing this svg to a temporary canvas and then remove that canvas once you take the screenshot using html2canvas.

Here is the link for canvg : https://github.com/canvg/canvg

Try this:

//find all svg elements in $container
//$container is the jQuery object of the div that you need to convert to image. This div may contain highcharts along with other child divs, etc
var svgElements= $container.find('svg');

//replace all svgs with a temp canvas
svgElements.each(function () {
    var canvas, xml;

    canvas = document.createElement("canvas");
    canvas.className = "screenShotTempCanvas";
    //convert SVG into a XML string
    xml = (new XMLSerializer()).serializeToString(this);

    // Removing the name space as IE throws an error
    xml = xml.replace(/xmlns=\"http:\/\/www\.w3\.org\/2000\/svg\"/, '');

    //draw the SVG onto a canvas
    canvg(canvas, xml);
    $(canvas).insertAfter(this);
    //hide the SVG element
    this.className = "tempHide";
    $(this).hide();
});

//...
//HERE GOES YOUR CODE FOR HTML2CANVAS SCREENSHOT
//...

//After your image is generated revert the temporary changes
$container.find('.screenShotTempCanvas').remove();
$container.find('.tempHide').show().removeClass('tempHide');
like image 83
shinobi Avatar answered Oct 08 '22 18:10

shinobi


As the html2canvas don't take svg elements, you need to convert all svg elements to canvas before you call the html2canvas method. You could use the canvg library to convert all the svg to canvas. You can pass the jquery object(which needs to convert from svg to canvas, can also be a parent element) to the following method:

function svgToCanvas (targetElem) {
var nodesToRecover = [];
var nodesToRemove = [];

var svgElem = targetElem.find('svg');

svgElem.each(function(index, node) {
    var parentNode = node.parentNode;
    var svg = parentNode.innerHTML;

    var canvas = document.createElement('canvas');

    canvg(canvas, svg);

    nodesToRecover.push({
        parent: parentNode,
        child: node
    });
    parentNode.removeChild(node);

    nodesToRemove.push({
        parent: parentNode,
        child: canvas
    });

    parentNode.appendChild(canvas);
});

html2canvas(targetElem, {
    onrendered: function(canvas) {
        var ctx = canvas.getContext('2d');
        ctx.webkitImageSmoothingEnabled = false;
        ctx.mozImageSmoothingEnabled = false;
        ctx.imageSmoothingEnabled = false;
    }
    });
}
like image 45
ABHILASH SB Avatar answered Oct 08 '22 16:10

ABHILASH SB


Your solution works beautifully. Since I am not using jQuery in my application, I had to change couple of lines in svgCanvas for getting the svg elements and iterating through them. The rest of the functions worked without any changes. My code is...

function svgToCanvas (targetElem) {
        var nodesToRecover = [];
        var nodesToRemove = [];

        var svgElems = document.getElementsByTagName("svg");

        for (var i=0; i<svgElems.length; i++) {
            var node = svgElems[i];
            var parentNode = node.parentNode;
            var svg = parentNode.innerHTML;

            var canvas = document.createElement('canvas');

            canvg(canvas, svg);

            nodesToRecover.push({
                parent: parentNode,
                child: node
            });
            parentNode.removeChild(node);

            nodesToRemove.push({
                parent: parentNode,
                child: canvas
            });

            parentNode.appendChild(canvas);
        }
}
like image 1
SrinivasG Avatar answered Oct 08 '22 18:10

SrinivasG