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You'll have to forgive my ignorance, but I'm not used to using wide character sets in c++, but is there a way that I can use wide string literals in c++ without putting an L in front of each literal?
If so, how?
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A wide string literal is a null-terminated array of constant wchar_t that is prefixed by ' L ' and contains any graphic character except the double quotation mark ( " ), backslash ( \ ), or newline character.
The only difference is that you cannot modify string literals, whereas you can modify arrays. Functions that take a C-style string will be just as happy to accept string literals unless they modify the string (in which case your program will crash).
String literals are arrays - objects of inherently unpredictable size (i.e of user-defined and possibly large size). In general case, there's simply no other way to represent such literals except as objects in memory, i.e. as lvalues . In C99 this also applies to compound literals, which are also lvalues .
String literal syntaxUse the escape sequence \\ to represent a backslash character as part of the string. You can represent a single quotation mark symbol either by itself or with the escape sequence \' . You must use the escape sequence \" to represent a double quotation mark.
No, there isn't. You have to use the L prefix (or a macro such as _T() with VC++ that expands to L anyway when compiled for Unicode).
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