How to use php array with sql IN operator?

Question

I have and array with two values and I want to use it with sql IN operator in select query.

Here is the structure of my table

id comp_id 1   2 2   3 3   1 

I have an array $arr which have two values Array ( [0] => 1 [1] => 2 )

I want to fetch the record of comp_id 1 and comp_id 2. So I wrote the following query.

SELECT * from table Where comp_id IN ($arr) 

But it does not return the results.

Answer 1

Since you have plain integers, you can simply join them with commas:

$sql = "SELECT * FROM table WHERE comp_id IN (" . implode(',', $arr) . ")"; 

If working with with strings, particularly untrusted input:

$sql = "SELECT * FROM table WHERE comp_id IN ('"       . implode("','", array_map('mysql_real_escape_string', $arr))       . "')"; 

Note this does not cope with values such as NULL (will be saved as empty string), and will add quotes blindly around numeric values, which does not work if using strict mysql mode.

mysql_real_escape_string is the function from the original mysql driver extension, if using a more recent driver like mysqli, use mysqli_real_escape_string instead.

However, if you just want to work with untrusted numbers, you can use intval or floatval to sanitise the input:

$sql = "SELECT * FROM table WHERE comp_id IN (" . implode(",", array_map('intval', $arr)) . ")";