Possible Duplicate:
MySQL check if a table exists without throwing an exception
I have a dynamic mysql query builder in my project that creates select queries from different tables.
 I need to check if the current processing table exists or not.
 Imagine that my tables are table1, table2, and table3. My code is something like this:  
<?php for($i = 1 ; $i <= 3 ; $i++) {    $this_table = 'table'.$i;    $query = mysql_query("SELECT * FROM $this_table");    // ... } ?>   How can I do this check (Please tell me the simplest way).
INFORMATION_SCHEMA provides access to database metadata, information about the MySQL server such as the name of a database or table, the data type of a column, or access privileges. Other terms that are sometimes used for this information are data dictionary and system catalog.
Updated mysqli version:
if ($result = $mysqli->query("SHOW TABLES LIKE '".$table."'")) {     if($result->num_rows == 1) {         echo "Table exists";     } } else {     echo "Table does not exist"; }   Original mysql version:
if(mysql_num_rows(mysql_query("SHOW TABLES LIKE '".$table."'"))==1)      echo "Table exists"; else echo "Table does not exist";   Referenced from the PHP docs.
Taken from another post
$checktable = mysql_query("SHOW TABLES LIKE '$this_table'"); $table_exists = mysql_num_rows($checktable) > 0; 
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