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I want to grep a file with a word, say "AAA", and it ends with whitespace or newlines. I know how to write this seperately, as follows, but having problems in combining them (in the sense that it outputs both VVV AAA and AAA VVV).
$echo -e "AAA VVV \nVVV AAA\nBBB" | grep "AAA$"
>VVV AAA
$echo -e "AAA VVV \nVVV AAA\nBBB" | grep "AAA[[:space:]]"
>AAA VVV
I have tried using [], but without success..
659
GNU grep supports three regular expression syntaxes, Basic, Extended, and Perl-compatible. In its simplest form, when no regular expression type is given, grep interpret search patterns as basic regular expressions. To interpret the pattern as an extended regular expression, use the -E ( or --extended-regexp ) option.
The wildcard * (asterisk) can be a substitute for any number of letters, numbers, or characters. Note that the asterisk (*) works differently in grep. In grep the asterisk only matches multiples of the preceding character. The wildcard * can be a substitute for any number of letters, numbers, or characters.
If you are looking for word AAA followed by space anywhere in the string, or at the end of line, then use
grep -P "AAA( |$)"
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