Divide string by line break or period with Python regular expressions

Question

I have a string:

"""Hello. It's good to meet you.
My name is Bob."""

I'm trying to find the best way to split this into a list divided by periods and linebreaks:

["Hello", "It's good to meet you", "My name is Bob"]

I'm pretty sure I should use regular expressions, but, having no experience with them, I'm struggling to figure out how to do this.

Answer 1

You don't need regex.

>>> txt = """Hello. It's good to meet you.
... My name is Bob."""
>>> txt.split('.')
['Hello', " It's good to meet you", '\nMy name is Bob', '']
>>> [x for x in map(str.strip, txt.split('.')) if x]
['Hello', "It's good to meet you", 'My name is Bob']

Answer 2

For your example, it would suffice to split on dots, optionally followed by whitespace (and to ignore empty results):

>>> s = """Hello. It's good to meet you.
... My name is Bob."""
>>> import re
>>> re.split(r"\.\s*", s)
['Hello', "It's good to meet you", 'My name is Bob', '']

In real life, you'd have to handle Mr. Orange, Dr. Greene and George W. Bush, though...