I'd like to use a variable
inside a regex
, how can I do this in Python
?
TEXTO = sys.argv[1] if re.search(r"\b(?=\w)TEXTO\b(?!\w)", subject, re.IGNORECASE): # Successful match else: # Match attempt failed
For example, the replacement pattern $1 indicates that the matched substring is to be replaced by the first captured group.
\\. matches the literal character . . the first backslash is interpreted as an escape character by the Emacs string reader, which combined with the second backslash, inserts a literal backslash character into the string being read. the regular expression engine receives the string \.
You have to build the regex as a string:
TEXTO = sys.argv[1] my_regex = r"\b(?=\w)" + re.escape(TEXTO) + r"\b(?!\w)" if re.search(my_regex, subject, re.IGNORECASE): etc.
Note the use of re.escape
so that if your text has special characters, they won't be interpreted as such.
From python 3.6 on you can also use Literal String Interpolation, "f-strings". In your particular case the solution would be:
if re.search(rf"\b(?=\w){TEXTO}\b(?!\w)", subject, re.IGNORECASE): ...do something
EDIT:
Since there have been some questions in the comment on how to deal with special characters I'd like to extend my answer:
raw strings ('r'):
One of the main concepts you have to understand when dealing with special characters in regular expressions is to distinguish between string literals and the regular expression itself. It is very well explained here:
In short:
Let's say instead of finding a word boundary \b
after TEXTO
you want to match the string \boundary
. The you have to write:
TEXTO = "Var" subject = r"Var\boundary" if re.search(rf"\b(?=\w){TEXTO}\\boundary(?!\w)", subject, re.IGNORECASE): print("match")
This only works because we are using a raw-string (the regex is preceded by 'r'), otherwise we must write "\\\\boundary" in the regex (four backslashes). Additionally, without '\r', \b' would not converted to a word boundary anymore but to a backspace!
re.escape:
Basically puts a backspace in front of any special character. Hence, if you expect a special character in TEXTO, you need to write:
if re.search(rf"\b(?=\w){re.escape(TEXTO)}\b(?!\w)", subject, re.IGNORECASE): print("match")
NOTE: For any version >= python 3.7: !
, "
, %
, '
, ,
, /
, :
, ;
, <
, =
, >
, @
, and `
are not escaped. Only special characters with meaning in a regex are still escaped. _
is not escaped since Python 3.3.(s. here)
Curly braces:
If you want to use quantifiers within the regular expression using f-strings, you have to use double curly braces. Let's say you want to match TEXTO followed by exactly 2 digits:
if re.search(rf"\b(?=\w){re.escape(TEXTO)}\d{{2}}\b(?!\w)", subject, re.IGNORECASE): print("match")
If you love us? You can donate to us via Paypal or buy me a coffee so we can maintain and grow! Thank you!
Donate Us With