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How to unpack xz file with python which contains only data but no filename?

I have a file, which I can decompress under linux using the following command:

unxz < file.xz > file.txt

How can I do the same using python? If I use python3 and the tarfile module and do the following:

import sys
import tarfile
try:
    with tarfile.open('temp.xz', 'r:xz') as t:
        t.extract()
except Exception as e:
    print("Error:", e.strerror)

I get the exception: ReadError('invalid header',). So apparently it expects some file- or directory information which is not present in the xz file.

So how can I decompress a file without header information?

like image 281
MiB_Coder Avatar asked Feb 07 '17 00:02

MiB_Coder


2 Answers

The tarfile module is only for... err... tar files. What you have here is not one.


XZ support is available in Python 3.3's LZMA module. In Python 2.x, you need backports.lzma.

try:
    import lzma
except ImportError:
    from backports import lzma

print lzma.open('file.xz').read()
like image 127
Charles Duffy Avatar answered Nov 16 '22 05:11

Charles Duffy


As noted by Charles in earlier comment,

Reading XZ-compressed text file in Python can be done with following (https://docs.python.org/3/library/lzma.html#lzma.open)

with lzma.open('test.txt.xz', mode='rt', encoding='utf-8') as fid:
    for line in fid:
        print(line)
like image 2
Jaakko Avatar answered Nov 16 '22 06:11

Jaakko