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How to submit value 1 if a checkbox in a checkbox array is checked, and submit 0 if it's unchecked? I tried this but no luck. I am trying to grab this array in a php array when the form is submitted. Please help!
<input id = 'testName0' type = 'checkbox' name = 'check[0]' value = '1' checked> <input id='testNameHidden0' type='hidden' value='0' name='check[0]'> <input id = 'testName1' type = 'checkbox' name='check[1]' value = '1' unchekced> <input id='testNameHidden1' type='hidden' value='0' name='check[1]'> <input type = 'submit' value = 'Save Changes'> > <script> if(document.getElementById('testName0').checked){ document.getElementById('testNameHidden0').disabled = true; } </script> <script> if(document.getElementById('testName1').checked){ document.getElementById('testNameHidden1').disabled = true; } </script> 
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If you need to submit a form when a checkbox is checked or when it is unchecked like when you are using a switch, a good way is to create an hidden input. If you try to submit the checkbox argument if the checkbox is unchecked the form will not be submitted at all.
Note: If a checkbox is unchecked when its form is submitted, there is no value submitted to the server to represent its unchecked state (e.g. value=unchecked ); the value is not submitted to the server at all.
First, select the checkbox using a DOM method such as getElementById() or querySelector() . Then, access the checked property of the checkbox element. If its checked property is true , then the checkbox is checked; otherwise, it is not.
attr("checked","checked"); To uncheck the checkbox: $("#checkboxid").
Simplest one, no javascript required, just put a hidden input before the checkbox:
<input type="hidden" name="check[0]" value="0" /> <input type="checkbox" name="check[0]" value="1" /> Inputs need to have the same name. If the checkbox is checked then value 1 will be submitted, otherwise value 0 from the hidden input.
Your case javascript solution, no hidden inputs needed:
<script type="text/javascript"> // when page is ready $(document).ready(function() { // on form submit $("#form").on('submit', function() { // to each unchecked checkbox $(this + 'input[type=checkbox]:not(:checked)').each(function () { // set value 0 and check it $(this).attr('checked', true).val(0); }); }) }) </script> <form method="post" id="form"> <input type="checkbox" name="check[0]" value="1" /> <input type="checkbox" name="check[1]" value="1" /> <input type="submit" value="Save Changes" /> </form> PHP solution, no hidden inputs needed:
<?php // if data is posted, set value to 1, else to 0 $check_0 = isset($_POST['check'][0]) ? 1 : 0; $check_1 = isset($_POST['check'][1]) ? 1 : 0; ?> <form method="post"> <input type="checkbox" name="check[0]" value="1" /> <input type="checkbox" name="check[1]" value="1" /> <input type="submit" value="Save Changes" /> </form> EDIT: the javascript solution is not valid anymore as of jquery 1.6. Based on this, a more proper solution is the following:
<script type="text/javascript"> // when page is ready $(document).ready(function() { // on form submit $("#form").on('submit', function() { // to each unchecked checkbox $(this).find('input[type=checkbox]:not(:checked)').prop('checked', true).val(0); }) }) </script> <form method="post" id="form"> <input type="checkbox" name="check[0]" value="1" /> <input type="checkbox" name="check[1]" value="1" /> <input type="submit" value="Save Changes" /> </form> If you love us? You can donate to us via Paypal or buy me a coffee so we can maintain and grow! Thank you!
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