How to strip the string which contain forward slash?

Question

i am new to python programming,trying to strip the string which contains forward slash character,i expected output as '/stack' but giving result as below. Could you help me how can i achieve expected output.Is there any other easy way to achieve the same.

>>> name='/stack/overflow'
>>> sub ='/overflow'
>>> name.strip(sub)
'stack'

Thanks in advance hema

Answer 1

The .strip method doesn't do what you think it does:

Docstring:
S.strip([chars]) -> string or unicode

Return a copy of the string S with leading and trailing
whitespace removed.
If chars is given and not None, remove characters in chars instead.
If chars is unicode, S will be converted to unicode before stripping

So what you're doing is saying "remove /,o,v,e,r,f,l,o, and w from the beginning or end of this string."

Instead, try splitting on /, taking all but the last element, and rejoining:

In [12]: '/'.join("/stack/overflow".split('/')[:-1])
Out[12]: '/stack'

If you actually just want to remove the substring '/overflow', you can do:

In [15]: "/stack/overflow".replace('/overflow', '')
Out[15]: '/stack'

Answer 2

First you need to check which OS you are using,

if its Linux/Unix

normally the file path is denoted by /

so you can simply use,

>>>name = '/stack/overflow'

>>>name.split(os.sep)  # Here os.sep is nothing but "/"

['', 'stack', 'overflow']

if it's windows,

just use

>>> name.split("/")
['', 'stack', 'overflow']