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I'm trying to capture a block of text into a variable, with newlines maintained, then echo it.
However, the newlines don't seemed to be maintained when I am either capturing the text or displaying it.
Any ideas regarding how I can accomplish this?
Example:
#!/bin/bash read -d '' my_var <<"BLOCK" this is a test BLOCK echo $my_var Output:
this is a test
Desired output:
this
is
a
test
727
To add multiple lines to a file with echo, use the -e option and separate each line with \n. When you use the -e option, it tells echo to evaluate backslash characters such as \n for new line. If you cat the file, you will realize that each entry is added on a new line immediately after the existing content.
Bash Escape Characters For example, if we have a multiline string in a script, we can use the \n character to create a new line where necessary. Executing the above script prints the strings in a new line where the \n character exists.
echo $var ; ?> Using concatenation assignment operator: We can use the concatenation assignment operator . = to concatenate two strings and the PHP_EOL to mark the end of the line.
The echo command is used to display a line of text that is passed in as an argument. This is a bash command that is mostly used in shell scripts to output status to the screen or to a file.
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