How to start up spring-boot application via command line?

Question

I have a spring-boot application which I need to start up by going to the folder directory and start up my web application via command line. I have a class called Application.java and the code inside it is as followed.

@SpringBootApplication(scanBasePackages = {"com.ubs.tas.topcat.dashboard"}) public class Application extends SpringBootServletInitializer {     private static final Logger LOGGER = LoggerFactory.getLogger(Application.class.getName());     private static final Class<Application> applicationClass = Application.class;      @Override     protected SpringApplicationBuilder configure(SpringApplicationBuilder application) {         return application.sources(applicationClass);     }      public static void main(String[] args) {         LOGGER.info("Starting...");         SpringApplication.run(Application.class, args);     } } 

I set up classpath then tried to run the command "java ApplicationUtility" but I'm getting this error message "Could not find the main class: ApplicationUtility. Program will exist."

Answer 1

I presume you are trying to compile the application and run it without using an IDE. I also presume you have maven installed and correctly added maven to your environment variable.

To install and add maven to environment variable visit Install maven if you are under a proxy check out add proxy to maven

Navigate to the root of the project via command line and execute the command

mvn spring-boot:run 

The CLI will run your application on the configured port and you can access it just like you would if you start the app in an IDE.

Note: This will work only if you have maven added to your pom.xml

Answer 2

You will need to build the jar file first. Here is the syntax to run the main class from a jar file.

java -jar path/to/your/jarfile.jar fully.qualified.package.Application