How to split a string of space separated numbers into integers?

Question

I have a string "42 0" (for example) and need to get an array of the two integers. Can I do a .split on a space?

Answer 1

Use str.split():

>>> "42 0".split()  # or .split(" ") ['42', '0'] 

Note that str.split(" ") is identical in this case, but would behave differently if there were more than one space in a row. As well, .split() splits on all whitespace, not just spaces.

Using map usually looks cleaner than using list comprehensions when you want to convert the items of iterables to built-ins like int, float, str, etc. In Python 2:

>>> map(int, "42 0".split()) [42, 0] 

In Python 3, map will return a lazy object. You can get it into a list with list():

>>> map(int, "42 0".split()) <map object at 0x7f92e07f8940> >>> list(map(int, "42 0".split())) [42, 0]