How to specify legend position in matplotlib in graph coordinates

Question

I am aware of the bbox_to_anchor keyword and this thread, which very helpfully suggests how to manually place the legend:

How to put the legend out of the plot

However, I'd like to use the coordinates of my x- and y-axis in the graph to specify the legend position (inside the plot), as I might need to move the figure into a large figure with a different axis environment, and I don't want to manually play around with those coordinates every time I do this. Is this possible?

Edit: A small example is here:

import numpy as n f, axarr = plt.subplots(2,sharex=True) axarr[1].set_ylim([0.611,0.675]) axarr[0].set_ylim([0.792,0.856])  axarr[0].plot([0, 0.04, 0.08],n.array([ 0.83333333,  0.82250521,0.81109048]), label='test1')  axarr[0].errorbar([0, 0.04, 0.08],n.array([ 0.8,  0.83,   0.82]),n.array([0.1,0.1,0.01]), label='test2')  axarr[1].plot([0, 0.04, 0.08],n.array([ 0.66666667,  0.64888304,  0.63042428])) axarr[1].errorbar([0, 0.04, 0.08],n.array([ 0.67,  0.64,  0.62]),n.array([ 0.01,  0.05,  0.1])) axarr[0].legend(bbox_to_anchor=(0.04, 0.82, 1., .102),labelspacing=0.1,       handlelength=0.1, handletextpad=0.1,frameon=False, ncol=4, columnspacing=0.7) 

I think what confuses me is that the legend does not actually start at 0.82, and indeed for my larger plot (with 5 subplots of this type), I need to use legend coordinates bbox_to_anchor=(0.04, 1.15, 1., .102) in order to make the legend appear on coordinates (0.02, 0.83). But maybe I am getting something else wrong?

Answer 1

The loc parameter specifies in which corner of the bounding box the legend is placed. The default for loc is loc="best" which gives unpredictable results when the bbox_to_anchor argument is used.
Therefore, when specifying bbox_to_anchor, always specify loc as well.

The default for bbox_to_anchor is (0,0,1,1), which is a bounding box over the complete axes. If a different bounding box is specified, is is usually sufficient to use the first two values, which give (x0, y0) of the bounding box.

Below is an example where the bounding box is set to position (0.6,0.5) (green dot) and different loc parameters are tested. Because the legend extents outside the bounding box, the loc parameter may be interpreted as "which corner of the legend shall be placed at position given by the 2-tuple bbox_to_anchor argument".

import matplotlib.pyplot as plt plt.rcParams["figure.figsize"] = 6, 3 fig, axes = plt.subplots(ncols=3) locs = ["upper left", "lower left", "center right"] for l, ax in zip(locs, axes.flatten()):     ax.set_title(l)     ax.plot([1,2,3],[2,3,1], "b-", label="blue")     ax.plot([1,2,3],[1,2,1], "r-", label="red")     ax.legend(loc=l, bbox_to_anchor=(0.6,0.5))     ax.scatter((0.6),(0.5), s=81, c="limegreen", transform=ax.transAxes)  plt.tight_layout()     plt.show() 

See especially this answer for a detailed explanation and the question What does a 4-element tuple argument for 'bbox_to_anchor' mean in matplotlib? .

---

If you want to specify the legend position in other coordinates than axes coordinates, you can do so by using the bbox_transform argument. If may make sense to use figure coordinates

ax.legend(bbox_to_anchor=(1,0), loc="lower right",  bbox_transform=fig.transFigure) 

It may not make too much sense to use data coordinates, but since you asked for it this would be done via bbox_transform=ax.transData.

Answer 2

Way I use very often is loc argument in the legend function. String input works well:

plt.legend(loc = "upper left") 

As documentation says, for the string referencing you can use:

        ===============   =============         Location String   Location Code         ===============   =============         'best'            0         'upper right'     1         'upper left'      2         'lower left'      3         'lower right'     4         'right'           5         'center left'     6         'center right'    7         'lower center'    8         'upper center'    9         'center'          10         ===============   =============