How to resolve TypeError: can only concatenate str (not "int") to str [duplicate]

Question

• I decided to make some kind of secret code for testing purposes with Unicode.
• I've done that by adding numbers to Unicode so it would be kind of secret.
• I've been getting this error, but I don't know how to solve it.
  • Is there any solution?

Original Code

message = input("Enter a message you want to be revealed: ") secret_string = "" for char in message:     secret_string += str(chr(char + 7429146)) print("Revealed", secret_string) q = input("") 

Original Error

--------------------------------------------------------------------------- TypeError                                 Traceback (most recent call last) <ipython-input-182-49ece294a581> in <module>       2 secret_string = ""       3 for char in message: ----> 4     secret_string += str(chr(char + 7429146))       5 print("Revealed", secret_string)       6 q = input("")  TypeError: can only concatenate str (not "int") to str 

Updated code

while True:     try:         message = int(input("Enter a message you want to be decrypt: "))         break     except ValueError:         print("Error, it must be an integer") secret_string = "" for char in message:     secret_string += chr(ord(char - str(742146))) print("Decrypted", secret_string) q = input("") 

Answer 1

Python working a bit differently to JavaScript for example, the value you are concatenating needs to be same type, both int or str...

So for example the code below throw an error:

print( "Alireza" + 1980) 

like this:

Traceback (most recent call last):   File "<pyshell#12>", line 1, in <module>     print( "Alireza" + 1980) TypeError: can only concatenate str (not "int") to str 

To solve the issue, just add str to your number or value like:

print( "Alireza" + str(1980)) 

And the result as:

Alireza1980 

Answer 2

instead of using " + " operator

print( "Alireza" + 1980) 

Use comma " , " operator

print( "Alireza" , 1980)