How to sort array in nodejs based on file size?

Question

I have an array with names of files as the entities of the array. I wanted to sort this array based on the size of the files.

For example,

var arr=['index.html','README.md','index.html']; 

So what I currently have is that I create an object with name of files as key and size of file as the value.

Now I am fetching these files from a remote location, so I can get the size of the file from content-length header.

Is there a better way to do it? Will it be possible to do this locally by which I mean read file size and create an object based on that?

Answer 1

Try this:

var arr = ['index.html','README.md','index.html'];

arr.sort(function(a, b) {
  return fs.statSync(a).size - fs.statSync(b).size;
});

I assume that these files are in your current directory.

Answer 2

Short memoized version without promises:

var arr = ['index.html', 'README.md', 'index.html'];
var sortedArray = arr
    // get the size of each file
    .map(file => { return { file: file, size: fs.statSync(file).size } })
    // sort by size ascending
    .sort((a, b) => a.size > b.size)
    // return a simple sorted array of the file names only
    .map(f => f.file);

console.log(sortedArray);