When iterating over arguments (for example) thats the most straightforward way to skip the first N elements?
eg:
use std::env; fn main() { for arg in env::args() { println!("Argument: {}", arg); } }
I tried env::args()[1..]
but slicing isn't supported.
Whats the simplest way to skip the first arguments of an iterator?
Call next() once to discard the first row.
We use the continue control statement to skip to the next iteration of the loop.
In Rust, iterators are lazy, meaning they have no effect until you call methods that consume the iterator to use it up.
collect() can take all the values in an Iterator 's stream and stick them into a Vec . And the map method is now generating Result<i32, &str> values, so everything lines up.
How can I skip the Nth element in a Rust iterator? Bookmark this question. Show activity on this post. Iterators have a skip method that skips the first n elements: let list = vec! [1, 2, 3]; let iterator = list.iter (); let skip_iter = iterator.skip (2); //skip the first 2 elements
If you need fused iterator, use fuse. Creates an iterator that skips the first n elements. skip (n) skips elements until n elements are skipped or the end of the iterator is reached (whichever happens first). After that, all the remaining elements are yielded.
Rust iterators are fundamental to the language and can be found in a variety of contexts. Consuming iterators returned from functions in the standard library and crates is straightforward. Eventually, however, you'll want to return iterators from your own functions.
It is also not specified what this iterator returns after the first None is returned. If you need fused iterator, use fuse. Creates an iterator that skips the first n elements. skip (n) skips elements until n elements are skipped or the end of the iterator is reached (whichever happens first). After that, all the remaining elements are yielded.
Turns out the .skip()
method can be used, eg:
use std::env; fn main() { for arg in env::args().skip(1) { println!("Argument: {}", arg); } }
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