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Calling Array#shuffle shuffles an array randomly, but I want to shuffle reproducibly – i.e., the same way every time. Is there a method for that? I want to call, for example, shuffle_with_key(123) and get the same result every time.
788
Method 4: In this method we will select 2 indices randomly and then swap them. This process will be randomly repeated up to n/2 to n times, Where n is the length of array. Method 5: This is the one of the most efficient methods, it is the Fisher–Yates shuffle Algorithm.
Shuffling a sequence of numbers have always been a useful utility, it is nothing but rearranging the elements in an array. Knowing more than one method to achieve this can always be a plus. Let’s discuss certain ways in which this can be achieved. Method 1: In this method we use shuffle () method from numpy library.
Let’s discuss a particular case. Shuffling an array of values is considered one of the oldest problems in computer science. Shuffling is possible with the Fisher-Yates shuffle algorithm for generating a random permutation of a finite sequence. That is to say, the algorithm shuffles the sequence.
If the length of the array is even then we can easily Swap 2 Variables without using 3rd variable for every pair of contiguous elements. If the length of the array is odd then we can do the same as above, but the last 3 elements will not form a pair, So will we can easily Swap those 3 Variables without using 4th variable.
Array#shuffle can take a seeded Random instance.
a = [1,2,3,4]
seed = 1
a.shuffle(random: Random.new(seed))
# => [4, 1, 3, 2]
a.shuffle(random: Random.new(seed))
# => [4, 1, 3, 2]
Just replace seed = 1 with whatever random seed you want to use.
152
Yes there is. Look the below :
(arup~>~)$ pry --simple-prompt
>> a = [ 1, 2, 3 ]
=> [1, 2, 3]
>> a.shuffle(random: Random.new(1))
=> [1, 3, 2]
>> a.shuffle(random: Random.new(1))
=> [1, 3, 2]
>> a.shuffle(random: Random.new(1))
=> [1, 3, 2]
>> a.shuffle(random: Random.new(1))
=> [1, 3, 2]
>> a.shuffle(random: Random.new(1))
=> [1, 3, 2]
>> a.shuffle(random: Random.new(2))
=> [3, 2, 1]
>> a.shuffle(random: Random.new(2))
=> [3, 2, 1]
>> a.shuffle(random: Random.new(2))
=> [3, 2, 1]
Read the documentation of shuffle(random: rng) → new_ary
The optional rng argument will be used as the random number generator.
You method would look like :-
def shuffle_with_key(ary,rng)
ary.shuffle(random: Random.new(rng))
end
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