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I want to add sub arrays to one single array in php [duplicate]

i have array like this.........

Array
(
    [0] => Array
        (
            [0] => rose
            [1] => monkey
            [2] => donkey
        )

    [1] => Array
        (
            [0] => daisy
            [1] => monkey
            [2] => donkey
        )

    [2] => Array
        (
            [0] => orchid
            [1] => monkey
            [2] => donkey
        )

)

and i want like this.........

Array
(
    [0] => rose
    [1] => monkey
    [2] => donkey
    [3] => daisy
    [4] => monkey
    [5] => donkey
    [6] => orchid
    [7] => monkey
    [8] => donkey
)

....I used array merge but it's not working because my array generates dymaically and each time shows different arrays. problem is I can't pass arrays dynamically in array_merge() function.It accepts only manually entries of array and not accepts any other variable .function accepts only array.

it works like this ...

$total_data = array_merge($data[0],$data[1],$data[2]);

as each time it generates different numbers of array dynamically so i have to use like this....

$data_array = $data[0],$data[1],$data[2];

 $total_data = array_merge($data_array);

but it shows an error "array_merge() [function.array-merge]: Argument #1 is not an array"......

like image 939
steve Avatar asked Feb 19 '13 07:02

steve


2 Answers

Try this :

$array  = your array

$result = call_user_func_array('array_merge', $array);

echo "<pre>";
print_r($result);

Or try this :

function array_flatten($array) {

   $return = array();
   foreach ($array as $key => $value) {
       if (is_array($value)){ $return = array_merge($return, array_flatten($value));}
       else {$return[$key] = $value;}
   }
   return $return;

}

$array  = Your array

$result = array_flatten($array);

echo "<pre>";
print_r($result);
like image 118
Prasanth Bendra Avatar answered Oct 20 '22 20:10

Prasanth Bendra


try this.....

       $result = array();
        foreach($data  as $dat)

          {
                foreach($dat as $d) 

                 {
                   $result[] = $d;

                 }

           }
like image 39
Venkata Krishna Avatar answered Oct 20 '22 22:10

Venkata Krishna