How would you share the same object between two other objects? For instance, I'd like something in that flavor:
class A
{
private string foo_; // It could be any other class/struct too (Vector3, Matrix...)
public A (string shared)
{
this.foo_ = shared;
}
public void Bar()
{
this.foo_ = "changed";
}
}
...
// inside main
string str = "test";
A a = new A(str);
Console.WriteLine(str); // "test"
a.Bar();
Console.WriteLine(str); // I get "test" instead of "changed"... :(
Here, I don't want to give a ref to the Bar method. What I want to achieve is something that would look like that in C++:
class A
{
int* i;
public:
A(int* val);
};
A::A (int* val)
{
this->i = val;
}
I read there is some ref/out stuff, but I couldn't get what I'm asking here. I could only apply some changes in the methods scope where I was using ref/out arguments... I also read we could use pointers, but is there no other way to do it?
This has nothing to do with sharing objects. You passed a reference to a string into the A constructor. That reference was copied into the private member foo_
. Later, you called B()
, which changed foo_
to "changed".
At no time did you modify str
. str
is a local variable in main
. You never passed a reference to it.
If you had wanted to change str
, you could have defined B as
public void Bar(ref string s)
{
this.foo_ = "changed";
s = this.foo_;
}
Consider:
public class C
{
public int Property {get;set;}
}
public class A
{
private C _c;
public A(C c){_c = c;}
public void ChangeC(int n) {_c.Property = n;}
}
public class B
{
private C _c;
public B(C c){_c = c;}
public void ChangeC(int n) {_c.Property = n;}
}
in main:
C myC = new C() {Property = 1;}
A myA = new A(myC);
B myB = new B(myC);
int i1 = myC.Property; // 1
myA.ChangeC(2);
int i2 = myC.Property; // 2
myB.ChangeC(3);
int i3 = myC.Property; // 3
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