How to set the first day of current week to Tuesday in Swift 3? The schedule will update every Tuesday so the first day have to start from Tuesday.
and then display on label :
thisWeekDate.text! = "\(first day of current week) - \(last day of current week)"
Full code.
let today = NSDate()
let nextTue = Calendar.current.date(byAdding: .day, value: 6, to: today as Date)
let formatter = DateFormatter()
formatter.dateFormat = "yyyy-MM-dd"
let todayString = formatter.string(from: today as Date)
let nextString = formatter.string(from: nextTue!)
formatter.dateFormat = "dd-MMM-yyyy"
let calendar = NSCalendar(calendarIdentifier: NSCalendar.Identifier.gregorian)
let components = calendar!.components([.weekday], from: today as Date)
//Label code
thisWeekDate.text! = "\(first day of current week) - \(last day of current week)"
//If i can change the first day of current week this weekly update code can be deleted
if components.weekday == 3 {
print("Hello Tuesday")
thisWeekDate.text! = "\(todayString) - \(nextString)"
UserDefaults.standard.set(todayString, forKey: "todayStringKey")
_ = UserDefaults.standard.object(forKey: "todayStringKey") as? String
UserDefaults.standard.set(nextString, forKey: "nextStringKey")
_ = UserDefaults.standard.object(forKey: "nextStringKey") as? String
} else {
print("It's not Tuesday")
let RetrivedDate_1 = UserDefaults.standard.object(forKey: "todayStringKey") as? String
let RetrivedDate_2 = UserDefaults.standard.object(forKey: "nextStringKey") as? String
if let date_1 = RetrivedDate_1, let date_2 = RetrivedDate_2 {
thisWeekDate.text! = "\(date_1) - \(date_2)"
}
}
App Design Screenshot
Create a custom Gregorian calendar and set the first weekday to Tuesday
var customCalendar = Calendar(identifier: .gregorian)
customCalendar.firstWeekday = 3
Then you can get the week interval with
var startDate = Date()
var interval = TimeInterval()
customCalendar.dateInterval(of: .weekOfMonth, start: &startDate, interval: &interval, for: Date())
let endDate = startDate.addingTimeInterval(interval - 1)
print(startDate, endDate)
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