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how to set or initialize default value for all elements of a table or 2d array or multdimentional array

Tags:

c++

arrays

I want to set a default nonzero value for all elements of a table or 2d array. array[size]={12} sets first elements only 12 and others are all 0 in a row.But fill(array,array+size,12) sets all elements to 12 in a row only.I could't apply this for 2d array.Is there any way to do this using fill() or any way without direct initialization using double for loop

#include <iostream>
#include<algorithm>
#include<vector>
#include<stdlib.h>
using namespace std;

int main()
{
   int arra[10][10];//declare 2d array

  for(int k=0;k<10;k++)//takes k's value 10 for 10 rows
     fill(arra,arra+10,45);//select a row and set all columns to 45 didn't work

}

array initialization http://www.fredosaurus.com/notes-cpp/arrayptr/array-initialization.html

like image 855
Sofi Ullah Saikat Avatar asked May 04 '16 11:05

Sofi Ullah Saikat


2 Answers

For C arrays, you'll probably want to use memset. You've marked this as C++, though, so I feel obliged to give a C++ answer:

std::vector<std::vector<int>> v(10, std::vector<int>(10, 45));

This creates a std::vector of 10 std::vector<int>s of size 10 with each element initialized to 45.

See here for the ideone.

like image 52
erip Avatar answered Sep 29 '22 09:09

erip


Almost the same way as you would with a 1-dimensional array:

#include <iostream>
#include <iomanip>

int main() {
    int arr[10][10] = {
        {  1,  2,  3,  4,  5,  6,  7,  8,  9, 10 },
        {  2,  4,  6,  8, 10, 12, 14, 16, 18, 20 },
        {  3,  6,  9, 12, 15, 18, 21, 24, 27, 30 },
        {  4,  8, 12, 16, 20, 24, 28, 32, 36, 40 },
        {  5, 10, 15, 20, 25, 30, 35, 40, 45, 50 },
        {  6, 12, 18, 24, 30, 36, 42, 48, 54, 60 },
        {  7, 14, 21, 28, 35, 42, 49, 56, 63, 70 },
        {  8, 16, 24, 32, 40, 48, 56, 64, 72, 80 },
        {  9, 18, 27, 36, 45, 54, 63, 72, 81, 90 },
        { 10, 20, 30, 40, 50, 60, 70, 80, 90, 100 }
    };

    for(int i=0; i<10; ++i) {
        for(int j=0; j<10; ++j) {
            std::cout << std::setw(4) << arr[i][j];
        }
        std::cout << '\n';
    }
}

NOTE: The first index does not require a value. In that case the compiler will automatically calculate this index.

int arr[][10] = { ... };

EDIT

An alternative that will avoid a double loop is:

## Heading ###include <iostream>
#include <iomanip>


int main() {
    int arr[10][10] = {}; // Initializes all values to 0
    for(int i=0; i<10; ++i ) arr[i][0] = 12;

    for(int i=0; i<10; ++i) {
        for(int j=0; j<10; ++j) {
            std::cout << std::setw(4) << arr[i][j];
        }
        std::cout << '\n';
    }
}
like image 33
TAS Avatar answered Sep 29 '22 08:09

TAS