Let's say I have a table with usernames:
Id | Name
-----------
1 | Bobby
20 | Bob
90 | Bob
100 | Joe-Bob
630 | Bobberino
820 | Bob Junior
I want to return a list of n
matches on name for 'Bob' where the resulting set first contains exact matches followed by similar matches.
I thought something like this might work
SELECT TOP 4 a.* FROM
(
SELECT * from Usernames WHERE Name = 'Bob'
UNION
SELECT * from Usernames WHERE Name LIKE '%Bob%'
) AS a
but there are two problems:
I am looking for a query that will return (for TOP 4)
Id | Name
---------
20 | Bob
90 | Bob
(and then 2 results from the LIKE query, e.g. 1 Bobby and 100 Joe-Bob)
Is this possible in a single query?
You could use a case
to place the exact matches on top:
select top 4 *
from Usernames
where Name like '%Bob%'
order by
case when Name = 'Bob' then 1 else 2 end
Or, if you're worried about performance and have an index on (Name)
:
select top 4 *
from (
select 1 as SortOrder
, *
from Usernames
where Name = 'Bob'
union all
select 2
, *
from Usernames
where Name like '%Bob%'
and Name <> 'Bob'
and 4 >
(
select count(*)
from Usernames
where Name = 'Bob'
)
) as SubqueryAlias
order by
SortOrder
A slight modification to your original query should solve this. You could add in an additional UNION that matches WHERE Name LIKE 'Bob%'
and give this priority 2, changing the '%Bob'
priority to 3 and you'd get an even better search IMHO.
SELECT TOP 4 a.* FROM
(
SELECT *, 1 AS Priority from Usernames WHERE Name = 'Bob'
UNION
SELECT *, 2 from Usernames WHERE Name LIKE '%Bob%'
) AS a
ORDER BY Priority ASC
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