How do you do many to many table outer joins?

Question

I have 3 tables, foo, foo2bar, and bar. foo2bar is a many to many map between foo and bar. Here are the contents.

select * from foo
+------+
| fid  |
+------+
|    1 |
|    2 |
|    3 |
|    4 |
+------+

select * from foo2bar
+------+------+
| fid  | bid  |
+------+------+
|    1 |    1 |
|    1 |    2 |
|    2 |    1 |
|    2 |    3 |
|    4 |    4 |
+------+------+

select * from bar
+------+-------+------+
| bid  | value | zid  |
+------+-------+------+
|    1 |     2 |   10 |
|    2 |     4 |   20 |
|    3 |     8 |   30 |
|    4 |    42 |   30 |
+------+-------+------+

What I want to request is, "Give me a list of all the fid and values with zid of 30"

I expect an answer for all the fids, so the result would look like:

+------+--------+
| fid  | value  |
+------+--------+
|    1 |   null |
|    2 |      8 |
|    3 |   null |
|    4 |     42 |
+------+--------+

Answer 1

SELECT * FROM foo
  LEFT OUTER JOIN (foo2bar JOIN bar ON (foo2bar.bid = bar.bid AND zid = 30))
  USING (fid);

Tested on MySQL 5.0.51.

This is not a subquery, it just uses parentheses to specify the precedence of joins.

Answer 2

SELECT * FROM
        foo LEFT JOIN
        (
        Foo2bar JOIN bar
             ON foo2bar.bid = bar.bid AND zid = 30
        )
        ON foo.fid = foo2bar.fid;

untested