Pandas Series: between() function The between() function is used to get boolean Series equivalent to left <= series <= right. This function returns a boolean vector containing True wherever the corresponding Series element is between the boundary values left and right. NA values are treated as False.
Consider also series between:
df = df[df['closing_price'].between(99, 101)]
You should use ()
to group your boolean vector to remove ambiguity.
df = df[(df['closing_price'] >= 99) & (df['closing_price'] <= 101)]
there is a nicer alternative - use query() method:
In [58]: df = pd.DataFrame({'closing_price': np.random.randint(95, 105, 10)})
In [59]: df
Out[59]:
closing_price
0 104
1 99
2 98
3 95
4 103
5 101
6 101
7 99
8 95
9 96
In [60]: df.query('99 <= closing_price <= 101')
Out[60]:
closing_price
1 99
5 101
6 101
7 99
UPDATE: answering the comment:
I like the syntax here but fell down when trying to combine with expresison;
df.query('(mean + 2 *sd) <= closing_price <=(mean + 2 *sd)')
In [161]: qry = "(closing_price.mean() - 2*closing_price.std())" +\
...: " <= closing_price <= " + \
...: "(closing_price.mean() + 2*closing_price.std())"
...:
In [162]: df.query(qry)
Out[162]:
closing_price
0 97
1 101
2 97
3 95
4 100
5 99
6 100
7 101
8 99
9 95
you can also use .between()
method
emp = pd.read_csv("C:\\py\\programs\\pandas_2\\pandas\\employees.csv")
emp[emp["Salary"].between(60000, 61000)]
Output
newdf = df.query('closing_price.mean() <= closing_price <= closing_price.std()')
or
mean = closing_price.mean()
std = closing_price.std()
newdf = df.query('@mean <= closing_price <= @std')
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