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How to see the javascript errors of PhoneGap app in Xcode?

I want to debug my PhoneGap app in Xcode, but its Console can not show javascript errors.

like image 518
mockee Avatar asked Oct 26 '10 09:10

mockee


3 Answers

The most elegant way to view and debug JavaScript errors in your Cordova/PhoneGap App is by attaching the Web Inspector from your Safari browser to the Web View in your iOS App (but, like Tom Clarkson already mentioned, you will need at least iOS 6).

  • On your iPad or iPhone use the Settings App to enable Web Inspector in the Advanced Settings for Safari
  • Connect your device to a Mac via USB (it will then appear under the Develop menu of Safari)
  • Start your App
  • Navigate to the Web View you want to debug
  • On the Mac, from the Safari Develop menu, select the name of your device and the App (its HTML-page), from its sub menu
  • A Web Inspector window will open, enabling you to browse the DOM, set breakpoints etc.

screen dump of Safari Develop menu on OS X

Apples documentation on setting this up

A thorough third party tutorial

Alternatively you could connect Chrome’s Web Inspector to iOS devices after installing iOS WebKit Debug Proxy. This also opens up the ability to do the inspection from Linux or Windows.

Remote access to your iOS’s HTML, CSS and JavaScript has gotten even more flexible nowadays because you can install the RemoteDebug iOS WebKit Adapter on top of aforementioned Debug Proxy. Because this adapter translates the WebKit Remote Debugging Protocol to the Chrome Debugging Protocol, these (on all their supported platforms) become available as alternative debugging and inspection tools:

  • Visual Studio Code
  • Chrome DevTools
  • Mozilla Debugger

BTW, remote debugging with the Safari Web Inspector works even in combination with the iOS Simulator.


Minimum version of Desktop Safari per iOS version

For each version of iOS you will need a specific minimum version of Desktop Safari in order to use remote web inspection, see the list below.

iOS 6
Safari 6+
iOS 7
Safari 6.1+
iOS 8
Safari 7.1+
iOS 9
Safari 8+
iOS 10
Safari 9+/10+? Please comment; always try Safari Technology Preview
iOS 11
Safari 11+
iOS 12
Safari 12+
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ᴠɪɴᴄᴇɴᴛ Avatar answered Nov 17 '22 15:11

ᴠɪɴᴄᴇɴᴛ


Paste the following somewhere near the start of your document so that it gets executed before any of your other JavaScript.

<script type="text/javascript">
    window.onerror = function(message, url, lineNumber) {
        console.log("Error: "+message+" in "+url+" at line "+lineNumber);
    }
</script>

And enjoy viewing details of your Javascript errors in the Xcode console window.

UPDATE: The above technique will log errors such as undefined variables. But syntax errors such as missing commas will still cause the entire script to break without logging anything.

Therefore you should add the following to the start of your onDeviceReady function:

console.log('Javascript OK');

If you don't see "JavaScript OK" appearing in your log window when the app launches, then it means you have a syntax error somewhere.

To save hunting for missing commas, the easiest thing is to paste your code into a Javascript validator such as this one:

http://www.javascriptlint.com/online_lint.php

and let it find the error for you.

Hopefully that takes some of the pain out of debugging.

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elMarquis Avatar answered Nov 17 '22 16:11

elMarquis


Note that with 0.9.2 (released today), console.log has been standardized across the platforms for logging (with debug.log deprecated).

There is a function that is available on the desktop WebView that is not exposed in the iOS UIWebView that will catch all errors (I'm trying to hack that functionality into a plugin, which uses private APIs, but the plugin would only be for development), but for now do what Kris suggested above and put try catch blocks on code and use console.log

To quickly catch possible syntax errors, when developing I have the page loaded in desktop Safari and quickly refresh it with the webkit error console viewable.

like image 9
Shazron Avatar answered Nov 17 '22 17:11

Shazron