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After a copy-paste from Wikipedia into Vim, I get this:
1 A 2 3 [+] Métier agricole<200e> – 44 P • 2 C 4 [×] Métier de l'ameublement<200e> – 10 P 5 [×] Métier de l'animation<200e> – 5 P 6 [+] Métier en rapport avec l'art<200e> – 11 P • 4 C 7 [×] Métier en rapport avec l'automobile<200e> – 10 P 8 [×] Métier de l'aéronautique<200e> – 15 P The problem is that <200e> is only a char.
I'd like to know how to put it in a search/replace (via the / or :).
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Note: Select the arrow at the bottom of the Find and Replace dialog box to show all options. On the Special menu, select the special character that you want to find. Select in the Replace with box. On the Special menu, select the special character that you want to use as a replacement.
If you are having a string with special characters and want's to remove/replace them then you can use regex for that. Use this code: Regex. Replace(your String, @"[^0-9a-zA-Z]+", "")
Alternatively, you can press Ctrl+H. Click in the “Find What” box and then delete any existing text or characters. Click the “More>>” button to open up the additional options, click the “Special” button, and then click the “Paragraph Mark” option from the dropdown list.
Check the help for \%u:
/\%d /\%x /\%o /\%u /\%U E678 \%d123 Matches the character specified with a decimal number. Must be followed by a non-digit. \%o40 Matches the character specified with an octal number up to 0377. Numbers below 040 must be followed by a non-octal digit or a non-digit. \%x2a Matches the character specified with up to two hexadecimal characters. \%u20AC Matches the character specified with up to four hexadecimal characters. \%U1234abcd Matches the character specified with up to eight hexadecimal characters.
These are sequences you can use. Looks like you have two bytes, so \%u200e should match it. Anyway, it's pretty strange. 20 in UTF-8 / ASCII is the space character, and 0e is ^N. Check your encoding settings.
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